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3 years ago

How do you write 55 another way

Mathematics

1 answer:

CaHeK987 [17]3 years ago

7 0

It can also be written as fifty-five.

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Order from least to greatest 457.2 415.138 828.142 452.018

Ratling [72]

415.138;452.018;457.2;828.142

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2 years ago

Read 2 more answers

Technological advances in farming made it possible to increase the crop of potatoes from 1 acre by 4 tons. As a result, from a f

zheka24 [161]

Answer:

Before: 8 tons

After: 12 tons

Step-by-step explanation:

3 0

3 years ago

if you deposit $8000 into an account paying 9% annual interest compunded semi anually how long will it take for your money to do

Anna007 [38]

Answer:

7.87 years

Step-by-step explanation:

#First we determine the effective annual rate based on the 9% compounded semi annual;

$i_m=(1+i/m)^m-1\\\\=(1+0.09/2)^2-1\\\\=0.09203$

#We then use this effective rate in the compound interest formula to solve for n. Given that the principal doubles after 2 yrs:

$A=P(1+i)^n\\\\A=2P, i=i_m\\\\16000=8000(1.09203)^n\\\\2=1.09203^n\\\\n=\frac{log \ 2}{log \ 1.09203}\\\\=7.87324\approx7.87 \ yrs$

Hence, it takes 7.87 years for the principal amount to double.

4 0

3 years ago

If events A and B are independent, and the probability that event A occurs is 83%, what must be true?

dexar [7]

Answer:

The true statement about the given conditional Probability is; The probability that event A occurs, given that event B occurs, is 83%.

5 0

1 year ago

Someone claims that the average amount of time that a freshman at TAMU studies is 7 hours. We think it’s higher than that and de

Stels [109]

Answer:

Test statistic t = 5.25

P-value = 0.000002 (one-tailed test)

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average amount of time that a freshman at TAMU studies is significantly higher than 7 hours.

Then, the null and alternative hypothesis are:

$H_0: \mu=7\\\\H_a:\mu> 7$

The significance level is 0.05.

The sample has a size n=49.

The sample mean is M=8.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=√s^2=√4=2.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{2}{\sqrt{49}}=0.29$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{8.5-7}{0.29}=\dfrac{1.5}{0.29}=5.25$

The degrees of freedom for this sample size are:

$df=n-1=49-1=48$

This test is a right-tailed test, with 48 degrees of freedom and t=5.25, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=P(t>5.25)=0.000002$

As the P-value (0.000002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the average amount of time that a freshman at TAMU studies is significantly higher than 7 hours.

6 0

3 years ago