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2 years ago

Potassium chlorate (KClO3) decomposes to form potassium chloride (KCl) and pure oxygen (O2) gas as shown below.

1 answer:

7 0

The balanced chemical reaction is:

2KClO3 ----> 2KCl + 3O2

We are given the amount of oxygen gas to be produced from potassium chlorate. This will be the starting point for the calculations.

28.0 L O2 ( 1 mol / 22.4 L) (2 mol KClO3 / 3 mol O2) ( 122.55 g / 1 mol) = 102.13 g KClO3 is needed

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Read 2 more answers

How many mL of 3.0M HCl are needed to make 300.0 mL of a 0.10M HCl?

nalin [4]

Answer:

V₁ = 10 mL

Explanation:

Given data:

Initial volume of HCl = ?

Initial molarity = 3.0 M

Final molarity = 0.10 M

Final volume = 300.0 mL

Solution:

Formula:

M₁V₁ = M₂V₂

M₁ = Initial molarity

V₁ = Initial volume of HCl

M₂ =Final molarity

V₂ = Final volume

Now we will put the values.

3.0 M ×V₁ = 0.10 M×300.0 mL

3.0 M ×V₁ = 30 M.mL

V₁ = 30 M.mL /3.0 M

V₁ = 10 mL

3 0

3 years ago

A 222 N force is required to keep an object moving along a circular path with a diameter of 11.6 m at a speed of 7.60 m/s. What

Arte-miy333 [17]

Answer:

$m=22.3\ kg$

Explanation:

The expression for centrifugal force is shown below as:-

$F=\frac{m\times v^2}{r}$

Where, m is the mass of the object = ?

v is the velocity of the object = 7.60 m/s

r is the radius

F is the force = 222 N

Diamter = 11.6 m

Radius = d/2 = 11.6 m/2 = 5.8 m

Applying the values in the above expression as:-

$222=\frac{m\times {7.60}^2}{5.8}$

$57.76m=1287.6$

$m=22.3\ kg$

7 0

2 years ago