All categories

3 years ago

Potassium chlorate (KClO3) decomposes to form potassium chloride (KCl) and pure oxygen (O2) gas as shown below.

1 answer:

7 0

The balanced chemical reaction is:

2KClO3 ----> 2KCl + 3O2

We are given the amount of oxygen gas to be produced from potassium chlorate. This will be the starting point for the calculations.

28.0 L O2 ( 1 mol / 22.4 L) (2 mol KClO3 / 3 mol O2) ( 122.55 g / 1 mol) = 102.13 g KClO3 is needed

You might be interested in

What is the best description of what Becquerel observed in his experiment?

myrzilka [38]

The answer is: D.unstable nuclei emitting high-energy particles as they formed more stable compositions.

Those high-energy particles are alpha particles , beta particles , gamma radiation.

For example, the decay chain of ²³⁸U is called the uranium series.

Decay start with U-238 and ends with Pb-206. There are several alpha and beta minus decays.

Antoine Henri Becquerel (1852 – 1908) was a French physicist and the first person to discover evidence of radioactivity.

Becquerel wrapped fluorescing crystal (uranium salt potassium uranyl sulfate) in a cloth, along with the photographic plate and a copper Maltese cross.

Several days later, he discovered that a image of the cross appeared on the plate.

The uranium salt was emitting radiation.

Because of this discovery, Becquerel won a Nobel Prize for Physics in 1903, which he shared with Marie Curie and Pierre Curie.

5 0

3 years ago

Read 2 more answers

HELP!!!! ASAP!!!!!!!!!!<br><br> HOW ARE REACTANTS DIFFERENT FROM THE PRODUCTS ?

raketka [301]

Reactants are what make up the product.

7 0

4 years ago

Read 2 more answers

Which consequence of new fishing methods had the most immediate impact on the environment?

maxonik [38]

I believe the answer is D

4 0

3 years ago

Read 2 more answers

The concentrated sulfuric acid we use in the laboratory is 98.0% sulfuric acid by weight. Calculate the molality and molarity of

timama [110]

Answer : The molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

Solution : Given,

Density of solution = $1.83g/cm^3=1.83g/ml$

Molar mass of sulfuric acid (solute) = 98.079 g/mole

98.0 % sulfuric acid by mass means that 98.0 gram of sulfuric acid is present in 100 g of solution.

Mass of sulfuric acid (solute) = 98.0 g

Mass of solution = 100 g

Mass of solvent = Mass of solution - Mass of solute = 100 - 98.0 = 2 g

First we have to calculate the volume of solution.

$\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}=\frac{100g}{1.83g/ml}=54.64ml$

Now we have to calculate the molarity of solution.

$Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution}}=\frac{98.0g\times 1000}{98.079g/mole\times 54.64ml}=18.29mole/L$

Now we have to calculate the molality of the solution.

$Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{98.0g\times 1000}{98.079g/mole\times 2g}=499.59mole/Kg$

Therefore, the molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

7 0

3 years ago

Which equation has x = 5 as the solution?

Natali5045456 [20]

Answer:

x-10 should be the answer

8 0

3 years ago