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zepelin [54]
2 years ago
10

Farmers who raise cotton once used arsenic acid, H3AsO4, as a defoliant at harvest time. Arsenic acid is a polyprotic acid with

K1 = 2.5 × 10–4, K2 = 5.6 × 10–8, and K3 = 3 × 10–13. What is the pH of a 0.500 M solution of arsenic acid?
Chemistry
1 answer:
Bess [88]2 years ago
8 0

Answer:

pH = 1.95

Explanation:

For polyprotic acids, it is generally assumed that all H⁺ comes from the 1st ionization step. The amount of H⁺ delivered into solution for the 2nd and 3rd ionization steps are in the order of 10⁻⁴M and 10⁻⁶M respectively and provide very little change in pH from the quantity delivered in the 1st ionization step.

Therefore... the [H⁺] concentraion and pH are computed as follows...

[H⁺] = √Ka₁[H₃AsO₄] = √(2.5 x 10⁻⁴)(0.500) M = 0.1118M

pH = -log[H⁺] = -log(0.01118) = 1.95

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A 10 kg bicycle is rolling down a hill at 5 m/s, what is its momentum?
Yakvenalex [24]

Answer:

<h2>50 kg.m/s</h2>

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 10 × 5

We have the final answer as

<h3>50 kg.m/s</h3>

Hope this helps you

4 0
3 years ago
Using the equations 2 C₆H₆ (l) + 15 O₂ (g) → 12 CO₂ (g) + 6 H₂O (g)∆H° = -6271 kJ/mol C (s) + O₂ (g) → CO₂ (g) ∆H° = -393.5 kJ/m
Dafna11 [192]

Answer : The enthalpy for the reaction is 49.1 kJ/mol

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation reaction of C_6H_6 will be,

6C(s)+3H_2(g)\rightarrow C_6H_6(l)    \Delta H=?

The intermediate balanced chemical reaction will be,

(1) 2C_6H_6(g)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(l)    

\Delta H_1=-6271kJ/mole

(2) C(s)+O_2(g)\rightarrow CO_2(g)    

\Delta H_2=-393.5kJ/mole

(3) 2H_2(g)+O_2(g)\rightarrow 2H_2O(l)    

\Delta H_3=-483.6kJ/mole

Now we will reverse the reaction 1 and divide by 2, multiply reaction 2 by 6 and reaction 3 by 3/2 then adding all the equations, we get :

(1) 6CO_2(g)+3H_2O(l)\rightarrow C_6H_6(g)+\frac{15}{2}O_2(g)    

\Delta H_1=-\frac{-6271kJ/mole}{2}=3135.5kJ/mol

(2) 6C(s)+6O_2(g)\rightarrow 6CO_2(g)    

\Delta H_2=6\times (-393.5kJ/mole)=-2361kJ/mol

(3) 3H_2(g)+\frac{3}{2}O_2(g)\rightarrow 3H_2O(l)    

\Delta H_3=\farc{3}{2}\times (-483.6kJ/mole)=-725.4kJ/mol

The expression for enthalpy of formation of C_6H_6 will be,

\Delta H=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H=(3135.5kJ/mole)+(-2361kJ/mole)+(-725.4kJ/mole)

\Delta H=49.1kJ/mole

Therefore, the enthalpy for the reaction is 49.1 kJ/mol

7 0
3 years ago
I will mark brainliest if all answered or if you don’t want to answer them all please just answer 9-15
stira [4]

Answer:

9. b

10.d

11.f

12.g

13.e

14.a

16.a

17.d

18.c

19.a

Explanation:

4 0
2 years ago
To what category of elements does an element belong if it is a poor conductor of electricity
Crazy boy [7]
Nonmetals & Noble Gases
4 0
3 years ago
A hot gas flowing through a pipeline can be considered as a:________
k0ka [10]

Answer:

B) irreversible process

Explanation:

The process given here is irreversible.

7 0
3 years ago
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