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3 years ago

What do all elements in the same period of the periodic table have in common

Chemistry

2 answers:

Delvig [45]3 years ago

8 0

In the periodic table of elements, you can found all the elements grouped according to common characteristics.

You have three mine things: lines, columns, and blocks.

Blocks define the sequence in which the electron layers of the elements are filled.

Columns are called groups. The elements of a group have similar electronic configurations and the same amount of electrons on the last layer.

Lines are called periods. Those periods define the number of energy levels of each element.

Flauer [41]3 years ago

4 0

Atomic orbitals!!!!!!!!!!

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A solution is made by dissolving 26.42g of (NH4)2so4 in enough h2o to make 50.00ml of solution

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Moles of ammonium sulfate = 26.42/molar mass of (NH4)2SO4
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4 years ago

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An unknown concentration of sodium thiosulfate, Na2S2O3, is used to titrate a standardized solution of KIO3 with excess KI prese

Maru [420]

Answer: The molarity of $Na_2S_2O_3$ is 0.108 M

Explanation:

$KIO_3+5KI+3H_2SO_4\rightarrow 3K_2SO_4+3H_2O+3I_2$

$2Na_2S_2O_3+I_2\rightarrow Na_2S_4O_6+2NaI$

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

$\text{Moles of }KIO_3=\frac{0.0131mol/L\times 21.55}{1000}=2.8\times 10^{-4}mol$

1 mole of $KIO_3$ produces = 3 moles of $I_2$

$2.8\times 10^{-4}$ moles of $KIO_3$ produces = $\frac{3}{1}\times 2.8\times 10^{-4}=8.4\times 10^{-4}$ moles of $I_2$

Now 1 mole of $I_2$ uses = 2 moles of $Na_2S_2O_3$

$8.4\times 10^{-4}$ moles of $I_2$ uses = $\frac{2}{1}\times 8.4\times 10^{-4}=1.69\times 10^{-3}$ moles of $Na_2S_2O_3$

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution in L}}=\frac{1.69\times 10^{-3}\times 1000}{15.65}=0.108M$

The molarity of $Na_2S_2O_3$ is 0.108 M

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3 years ago