Answer:
2 seconds
Step-by-step explanation:
The formula h = -16t^2 +vt +s gives the vertical height (in feet) at time t (in seconds) for an object with an initial vertical velocity (in ft/s) of v and an initial height (in ft) of s. The problem statement tells us the ball's initial velocity is v=34 and the initial height is s=4.
Then the equation is ...
h = -16t^2 +34t +4
We want to find the value of t when h=8. There will be two solutions, one when the ball is going up, and the other when the ball is coming down. We are interested in the second solution.
8 = -16t^2 +34t +4
16t^2 -34t +4 = 0 . . . . . subtract the right side of the equation to put it into standard form
(16t -2)(t -2) = 0 . . . . . . factor the equation
Solutions are values of t that make the factors zero:
t = 2/16 or t = 2
It takes 2 seconds for the ball to come down to meet Mike's head.
Answer:
x < 4
Step-by-step explanation:
12 – 5x > -8
Subtract 12 from each side
12-12 – 5x > -8-12
-5x> -20
Divide each side by -5, remembering to flip the inequality
-5x/-5 < -20/-5
x < 4
Answer:
8
Step-by-step explanation:
8 can go into 88 and it can also go into 104 too and 8 is the largest number so the answer is C
Answer:
Step-by-step explanation:
12.
(A). AB = √34 units
(B). Area of triangle is 7.5 units²
Perimeter of triangle is (√34 + 8) units
(C). ΔA'BC is reflection of ΔABC over y = 2
(D). ΔA'BC is right angled. ΔABA' is isosceles.