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Brilliant_brown [7]
3 years ago
15

Can some one help me with this will give brainliest

Mathematics
1 answer:
a_sh-v [17]3 years ago
7 0
The first one would be C and the 2nd is A. 
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A boiler room has the shape of a rectangular prism. The area of the floor of the room is 112 square feet. The length of the room
Naddik [55]

Answer:

Length = 16 feet.

Width = 7 feet

Height = 8 feet

Volume = 896 cubic feet.

Step-by-step explanation:

There is a rectangular prism boiler room. 112 square feet is the floor area of the room.

Let the length of the room is L feet and width is W feet.

So, LW = 112 ...... (1)

Now, given that L = 2 + 2W ........ (2) , hence, from equation (1) we get  

(2 + 2W)W = 112

⇒ 2w + 2w² = 112

⇒ W² + W - 56 = 0

⇒ (W +8)(W - 7) = 0

⇒ W = 7 feet. {Neglecting the negative root as W can not be negative}

Hence, from equation (2) we get L = 2W + 2 = 16 feet.

Now, 1 foot more than the width is the height H.

Hence, H = 7 + 1 = 8 feet.

Therefore, the volume of the room is, V = LWH = 16 × 7 × 8 = 896 cubic feet. (Answer)

5 0
3 years ago
Find a point on the graph of the function y=f(x)+3
Fudgin [204]
In the general case, it is (x, y+3), where y = f(x).
5 0
3 years ago
Jacob made a banner for a sporting event in the shape of a parallelogram. The area of the banner is 127 1/2 square centimeters.
MAVERICK [17]

Answer:30

Step-by-step explanation: its 30 because you divide 127 1/2 or 127.5 by 4.25 or 4 1/4.

4 0
3 years ago
A cross-country train travels at a steady speed. It covers 15 miles in 20
skelet666 [1.2K]

Answer:

i think its 225 but i can still be wrong

5 0
3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
olchik [2.2K]

Answer:

14.52 seconds.

Step-by-step explanation:

We have been given that the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation y=-16x^2+224x+121. We are asked to find the time, when the rocket will hit the ground.

We know that the rocket will hit the ground, when height will be 0. So to find the time when rocket will hit the ground, we will substitute y=0 in our given equation as:

0=-16x^2+224x+121

Let us solve for x using quadratic formula.

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-224\pm\sqrt{224^2-4(-16)(121)}}{2(-16)}

x=\frac{-224\pm\sqrt{50176+7744}}{-32}

x=\frac{-224\pm\sqrt{57920}}{-32}

x=\frac{-224\pm240.66574}{-32}

x=\frac{-224+240.66574}{-32}, x=\frac{-224-240.66574}{-32}

x=\frac{16.66574}{-32}, x=\frac{-464.66574}{-32}

x=-0.520804375, x=14.520804375

Upon rounding to nearest 100th of second, we will get:

x\approx -0.52, x\approx 14.52

Since time cannot be negative, therefore, the rocket will hit the ground after 14.52 seconds.

6 0
3 years ago
Read 2 more answers
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