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Alecsey [184]
4 years ago
12

-2x+7=13x-5 looking for x

Mathematics
2 answers:
noname [10]4 years ago
4 0
Hey!

Let's start writing this problem.
-2x+7=13x-5
Subtract 7 from both sides.
-2x+7-7=13x-5-7
-2x=13x-12
Subtract 13x from both sides.
-2x-13x=13x-12-13x
-15x=-12
Divide both sides by -15.
\frac{-15x}{-15}=\frac{-12}{-15}
x=\frac{4}{5}

Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish
podryga [215]4 years ago
4 0
<span>-2x+7=13x-5
13x + 2x = 7 + 5
15x = 12
    x = 12/15
    x = 4/5</span>
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What are the vertical and horizontal asymptotes for the function f(x)=<br> 3x2/x2-4
Alecsey [184]

Answer:  f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.

Step-by-step explanation:

Given function: f(x)=\dfrac{3x^2}{x^2-4}

The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.

i.e. x^2-4=0\Rightarrow\ x^2=4\Rightarrow\ x=\pm2

Hence, f(x) will have vertical asymptotes at x=-2 and x=2.

To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.

So, the graph will horizontal asymptote at y=\dfrac{\text{Coefficient of }x^2\text{ in numerator}}{\text{Coefficient of }x^2\text{ in denominator}}

i.e. y=\dfrac{3}{1}=3

Hence, f(x) will have horizontal asymptote at y=3.

3 0
4 years ago
Solve 16 = –3y – 5 for y. A. y = 5 B. y = 7 C. y = –5 D. y = –7
grigory [225]

Answer:

B. y = 7

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Therefore y = 7

Hope it helps you

4 0
4 years ago
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