<u>Answer:</u> Amount of iron produced is 101.36 grams.
<u>Explanation:</u>
For the reaction of aluminium and iron oxide, the equation follows:
By Stoichiometry of the reaction,
When 1 mole of aluminium oxide is produced, then 2 moles of iron is also produced.
So, when 0.905 moles of aluminium oxide is produced, then 
of iron is also produced.
Now, to calculate the amount of iron produced, we use the equation:
Molar mass of iron = 56 g/mol
Moles of iron = 1.81 moles
Putting values in above equation, we get:
Hence, amount of iron produced is 101.36 grams.
In order to compute this, we must first take a couple of assumptions of:
1) The laboratory size so we can calculate its volume
2) The number of students working in the lab so we know the total gas produced
Let the lab be
11 m × 9 m × 6 m
The volume then computes to be:
594 m³
We know that
1 Liter is 1 dm³
1 m = 10 dm
1 m³ = 1000 dm³
Therefore, the room volume in liters is:
594,000 Liters
Let there be 30 students in the laboratory
Total gas being produced:
6 × 30
= 180 Liters
This works out to be:
0.03% of Hydrogen by volume
Therefore, there is no risk of explosion given our assumption of size and students.
Answer:
B. salt dissolved in water
Explanation:
a mixture is multiple substances mixed together
If you have 9 moles of hydrogen gas(H2) the moles of water that can be formed is 9 moles
<u><em>calculation</em></u>
2H2 +O2→ 2H2O
The mole of H2O is calculated using the mole ratio.
that is H2:H2O is 2:2 into simple form = 1:1
therefore if 9 moles of H2 reacted the moles of H2O = 9 x1/1 = 9 moles
Answer:
I believe the answer is 0.100.
Explanation:
Hope my answer has helped you!
