Molar mass of MgCO3 is 84.313 g/mol
You can calculate this from data on the periodic table:
Molar mass Mg = 24.305g/mol
molar mass C = 12.011g/mol
molar mass O = 15.999g/mol mass 3 mol = 47.997g
Total = 84.313g/mol
Mass to be used in 1.2L of 1.5M solution = 84.313g * 1.2L * 1.5mol /L = 151.763g
I have not taken significant figures into account
The balanced equation you provide is not necessary in this calculation
Answer:
Q1. C
Q2 and Q3 are correct.
Explanation:
Since F=ma, and the force is a constant,
for the greatest acceleration, the mass of the ball must be the least.
Thus ball C has the greatest acceleration.
Let's check:
A) F=ma
a=F/m
a= F/68
B) a=F/72
C) a= F/64 (✓)
The smaller the denominator, the larger the value of a.
(Think: 1/2 >1/3)
Answer:
200g or 40 teaspoons
Explanation:
An average human, weighing about 50 pounds, has about 200 g or 40 tps of NACl
