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2 years ago

5. What is the surface area of this figure? 7 yd 7 yd 5 yd 7 yd 7 yd

Mathematics

1 answer:

Mnenie [13.5K]2 years ago

8 0

Answer:

238

Step-by-step explanation:

the top and bottom are going to be, 7 x 7 aka 49.

all the sides will be, 7 x 5 aka 35.

49 + 49 + 35 + 35 + 35 + 35 = 238

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What is the length of the leg.s of the triangle below

Bingel [31]

Answer:

Step-by-step explanation:

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2 years ago

Outside temperature over a day can be modeled as a sinusoidal function. Suppose you know the temperature varies between 73 and 9

Naddika [18.5K]

Answer: After about 9.03 hours the temperature first reach 82 degrees.

Step-by-step explanation:

The sinusoidal function is given by :

$y=A\sin[\omega(x-\alpha)]+C$

where, A = amplitude; $\omega=\dfrac{2\pi}{period}$ , α= phase shift on the Y-axis and C = midline.

As per given,

Average daily temperature= $C=\dfrac{73+97}{2}=85$ [midline is average of upper and lower limit.]

A= 97-85 = 12

Phase shift: $\alpha=10$

Period = 24 hours;

$\omega=\dfrac{2\pi}{24}=\dfrac{\pi}{12}$

Substitute all values in sinusoidal function, we get

$y=12\sin[\dfrac{\pi}{12}(x-10)]+85$

Put y= 82, we get

$82=12\sin[\dfrac{\pi}{12}(x-10)]+85\\\\\Rightarrow\ -3= 12\sin[\dfrac{\pi}{12}(x-10)]\\\\=\dfrac{-1}{4}= \sin[\dfrac{\pi}{12}(x-10)]\\\\\Rightarrow\ \dfrac{\pi}{12}(x-10)=\sin^{-1}(\dfrac{-1}{4})\\\\\Rightarrow\ x-10=\dfrac{12}{\pi}(\sin^{-1}(\dfrac{-1}{4}))\\\\\Rightarrow\ x=\dfrac{12}{\pi}(\sin^{-1}(\dfrac{-1}{4}))+10\\\Rightarrow\ x\approx9.03$

Hence, After about 9.03 hours the temperature first reach 82 degrees.

3 0

2 years ago

32 feet per sec squared into inches

Natasha_Volkova [10]

It would be 32 x 12 because there are 12 inches per feet. So the answer would be 384 inches per sec squared. If this is right could you possibly give me brainliest? Hope this helped.

5 0

2 years ago

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X²+y²-6x+14y-1=0<br> and please show your work so I can learn

Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

$x^2 + y^2 -6x+14y-1=0$

We need to use the Quadratic Formula*

$x =\frac{-b+\sqrt{b^2}-4ac }{2a}$ , $\frac{-b-\sqrt{b^2} -4ac }{2a}$

Thus, given the problem:

$a = 1, b=-6, c=y^2+14y-1$

So now we just need to plug them in the Quadratic Formula*

$x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$ , $x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$

As you can see, it is a mess right now. Therefore, we need to simplify it

$x=\frac{6+2\sqrt{10-y^2-14y} }{2}$ , $x = \frac{6-2\sqrt{10-y^2-14y} }{2}$

Now that's get us to the final solution:

$x=3+\sqrt{10-y^2-14y}$ , $x=3-\sqrt{10-y^2-14y}$

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

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2 years ago

Which of the following values would complete the ordered pair if the point is on the graph of f (x) = -3x + 2 ?

Scrat [10]

Answer: the y-coordinate that completes the point is 5.

Explanation:

An ordered pair (x, y) indicates the x-and-y coordinates of a general point, where x is the input value of a function and y is the output value.

The output value is y = f(x) and must be found applying the rule (function) to the given input value.

In this case the rulte is f(x) = - 3x + 2, and the input value, x, is - 1 (the first value of the ordered pair).

This is the mathematical procedure:

x = - 1
f(x) = f (-1) = -3 (-1) + 2 = 3 + 2 = 5.

5 0

2 years ago

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