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chubhunter [2.5K]
3 years ago
5

Using the function below, calculate f(4).

Mathematics
1 answer:
Vinil7 [7]3 years ago
7 0

Answer:

D. 8

Step-by-step explanation:

Using the graph of the function above, f(4) can be easily determined by tracing the corresponding coordinate of x = 4. When x = 4, on the x-axis, y = 8 on the y-axis.

The value of f(4), simply means, what is the value of y when x = 4.

Thus, the value of f(4) = 8.

The right answer is D. 8.

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An electronics company wants to compare the quality of their cell phones to the cell phones from three of their competitors. The
skad [1K]

Answer:

The treatment should be stated by the four companies,since it more interested in the quality among each of the companies to be compared.

Step-by-step explanation:

From the example given, Since an electronic company wants to differentiate  their cell phones quality to the cell phones from their three main competitors.

If ANOVA is used to determine the average number of defects, then the treatment  should be defined for the four companies because it is more interested in comparing the quality among the different companies.

7 0
3 years ago
Ms. Jones is baking a cake for her students. She needs 2/3 cup of brown sugar to make the cake. Right now, she has 3/4 cup of br
ch4aika [34]
2/3= 0.6667 which you can figure out by 2÷3
3/4= 0.75 which you can figure out by 3÷4
because 0.75 is greater than 0.6667 she has enough to make the cake.
5 0
3 years ago
What is 5000 g equal to in kilograms?
MrRa [10]
A kilogram is 1000 grams. Therefore, 5000 g is 5 kg
5 0
3 years ago
Read 2 more answers
A customer owes $33.63 in transaction fees and he/she gives you $40.00. how much change should the customer receive back?
Nataliya [291]
The customer should receive $6.37 back
3 0
3 years ago
Give two different sequences of three transformations that would map PQR onto EFG given that PQR=EFG.
Gre4nikov [31]

9514 1404 393

Answer:

  1. Translate P to E; rotate ∆PQR about E until Q is coincident with F; reflect ∆PQR across EF
  2. Reflect ∆PQR across line PR; translate R to G; rotate ∆PQR about G until P is coincident with E

Step-by-step explanation:

The orientations of the triangles are opposite, so a reflection is involved. The various segments are not at right angles to each other, so a rotation other than some multiple of 90° is involved. A translation is needed in order to align the vertices on top of one another.

The rotation is more easily defined if one of the ∆PQR vertices is already on top of its corresponding ∆EFG vertex, so that translation should precede the rotation. The reflection can come anywhere in the sequence.

__

<em>Additional comment</em>

The mapping can be done in two transformations: translate a ∆PQR vertex to its corresponding ∆EFG point; reflect across the line that bisects the angle made at that vertex by corresponding sides.

3 0
3 years ago
Read 2 more answers
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