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Airida [17]
3 years ago
5

What is 5000 g equal to in kilograms?

Mathematics
2 answers:
Soloha48 [4]3 years ago
6 0
5000g equals 5kg because 1000g equals 1 kg so thats why 5000g is equal to 5 kg
MrRa [10]3 years ago
5 0
A kilogram is 1000 grams. Therefore, 5000 g is 5 kg
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What is the surface area of this rectangular prism that has 9 ft a width of 5 feet and a height of 7.5ft
daser333 [38]
To get your answer:

9 times 5 times two= 90
9 times 7.5 times two= 135
5 times 7.5 times two= 75

then add all of them together and you will get the surface area
90+135+75=300
you should have an answer of 300 feet²
6 0
3 years ago
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QveST [7]

Answer: 364 m squared

Step-by-step explanation:

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4 0
3 years ago
Slope : - 9/7 point : ( -7,4 )
dolphi86 [110]
To form an equation with the given information, we use the formula :

y = mx + b, m being the slope and b being the y-intercept.

Since it is given that the slope is -9/7, we substitute m with -9/7.

y = -9/7x + b

To find b, we will substitute the known coordinates into the equation :
At point (-7 , 4), x = -7, y = 4

4 = -9/7 (-7) + b
4  = 9 + b
b = 4 - 9
b = -5

Now we know that b = -5, we will substitute b = -5 into the equation that we found earlier, y = -9/7 x + b :

y = - 9/7x - 5

To make it more readable, we can multiply the equation by 7:
7y = -9x - 5
7y + 9x + 5 = 0

-----------------------------------------------------------
Answer : 7y + 9x + 5 = 0
-----------------------------------------------------------
7 0
3 years ago
What two rational expressions sum to 3x+4/x^2-6x+5?
Lubov Fominskaja [6]

Answer:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

Step-by-step explanation:

The given rational expression is:

\frac{3x+4}{x^{2}-6x+5} = \frac{3x+4}{(x-1)(x-5)}

We can use concept of Partial Fractions to solve this problem. Let,

\frac{3x+4}{(x-1)(x-5)}=\frac{A}{x-1} +\frac{B}{x-5}

Multiplying both sides by (x - 1)(x - 5), we get:

3x+4=A(x-5)+B(x-1)

Substituting x = 5, we get:

3(5)+4=A(5-5)+B(5-1)\\\\ 15+4=0+4B\\\\ 19=4B\\\\ B=\frac{19}{4}

Substituting x = 1, we get:

3(1)+4=A(1-5)+B(1-1)\\\\ 7=-4A\\\\ A=-\frac{7}{4}

Substituting the value of A and B, back in the original equation, we get:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

4 0
3 years ago
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