A field goal kicker makes 4 of 5 extra points during a game. what percent of extra points were made?
2 answers:
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Answer:
Expected Winnings = 2.6
Step-by-step explanation:
Since the probability of rolling a 1 is 0.22 and the probability of rolling either a 1 or a 2 is 0.42, the probability of rolling only a 2 can be determined as:
The same logic can be applied to find the probability of rolling a 3
The sum of all probabilities must equal 1.00, so the probability of rolling a 4 is:
The expected winnings (EW) is found by adding the product of each value by its likelihood:
Expected Winnings = 2.6
Answer:
The volume of the space between the balls and the rectangular box is
Step-by-step explanation:
The attachment below shows the description of the rectangular bow and the three spherical balls.
From the description,
- Two of the balls are each touching 5 sides of the rectangular box, say the 5 sides touched by one of the balls are sides 1,2,3,4, and 5; then the other ball will touch sides 2,3,4,5, and 6).
- The middle ball also touches four sides of the rectangular box, These four sides touched by the middle ball will be sides 2,3,4, and 5.
This means the balls are tightly fitted into the rectangular box.
Each of the balls has a radius r
Hence, The volume of one of the balls is given by the volume of a sphere
The volume occupied by one of the balls is
∴ The volume occupied by the three spherical balls will be
3 ×
=
The volume occupied by the three spherical balls
For the rectangular box,
The volume of a rectangular box =
Where is the length
is the width and
is the height
Since the balls are tightly packed,
The width of the rectangular box will be the diameter of the balls
diameter of the balls = 2r
∴ = 2r
The height of the rectangular box will also be the diameter of the balls
∴ = 2r
The length of the rectangular box will be 3 times the diameter of the balls
∴ = 3 × 2r = 6r
Hence,
The volume of a rectangular box = 6r × 2r × 2r
= 24r³
The volume of the space between the balls and the rectangular box is given by
Volume of the space between the balls and the rectangular box =
volume of the rectangular box - volume occupied by the three spherical balls
Volume of the space between the balls and the rectangular box= 24r³ - 4πr³
= 24r³ - 4πr³
= 4r³(6 - π)
