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Answer:
The parietal bone has not articulated with zygomatic bone.
Explanation:
Parietal bones are paired structure that form the roof and side of the cranium.
The parietal bones are articulated with each other and form suture.
It articulates occipital bone posteriorly,and anteriorly with the frontal bone which form a suture called as coronal suture.
Inferiorly the parietal bone is articulated with sphenoid and temporal bone.
Zygomatic bone is irregular shaped and paired structure that articulates with maxilla.temporal bone, sphenoid bone,frontal bone.
What work sheet? I'm great in Biology!
Answer:
Part A: Thr-Leu-Val
Part B: ACC-UUG-GUU
Explanation:
When you transcribe a DNA sequence to mRNA, you need to remember that in RNA there is no Thymine (T), instead it has Uracil (U). So the base pairings would be like this compared to DNA base pairing:
DNA RNA
A-T A-U
T-A T-A
C-G G-C
G-C C-G
Given the sequence the transcription will be as follows:
DNA : TGG - AAC - CAA
mRNA: ACC - UUG - GUU
Next, to translate it into amino acids, you will use the chart. Now amino acids pair in codons (3 base pairs at a time). Let's take the first codon in your sequence:
ACC
1st 2nd 3rd
A C C
Using the column on the left, find the row that matches it, so in this case A.
At the very top, there is another row of letters, looking at the row of A only, look for the column of the second base which is C.
Lastly, look at the right most column and find the letter that matches the third base within the box where A and C intersect. In this case, C is your third base.
The amino acid where all three intersect is your first amino acid which is Thr.
Just do this for the next codons and you will come up with the answer.
Answer is: <span>nondisjunction.
</span>Nondisjunction<span> is the failure of </span>homologous chromosomes<span> to separate correctly during </span>cell division, because of tha daughter cells have abnormal chromosome numbers. This example is <span>failure of a pair of </span>homologous chromosomes<span> to separate in </span><span>meiosis I.</span>
