All categories

2 years ago

I REALLY need help with this plzzz help 90 points for whoever answer + branliest

Mathematics

1 answer:

aliina [53]2 years ago

4 0

$\purple{ \tt{ \huge{ \: ✨Answer ✨ \: }}}$

$The \: \: answer \: \: is \: \: \red{ \boxed{ \boxed{ \huge{ \tt{ \: B. \: \frac{1}{ {x}^{5} {y}^{9}}}}}} }$

You might be interested in

30 POINTS!!!!!

Whitepunk [10]

Answer:

A third group that does not use a cell phone before bedtime

Step-by-step explanation:

Both groups have the use of a cellphone before bedtime, and the amount used would affect their time to fall asleep, but another group is needed that doesn't use a cellphone to calculate the effect of it not being used and seeing the results.

8 0

1 year ago

Find the circumference of a sphere's great circle with a radius of 4 m.

Ulleksa [173]

This is the concept of areas and circumference of the solid figures;
The circumference of the cylinder whose radius is 4 m will be given by;
C=2πr
C=2*π*4
C=8π m=25.133 m

3 0

2 years ago

The robot poured too many ingredients in and had 1/2 cup of apple pie filling left .He decid d to split it up and put an equal a

Alona [7]

1/6 cup is the answer

8 0

3 years ago

Read 2 more answers

An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh

natima [27]

Answer:

Speed of the plane in still air: $779\; {\rm km \cdot h^{-1}}$ .

Windspeed: $100\; {\rm km \cdot h^{-1}}$ .

Step-by-step explanation:

Assume that $x\; {\rm km \cdot h^{-1}}$ is the speed of the plane in still air, and that $y\; {\rm km \cdot h^{-1}}$ is the speed of the wind.

When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be $(x - y)\; {\rm km \cdot h^{-1}}$ .
When this plane is travelling in the same direction as the wind, the ground speed of this plane would be $(x + y)\; {\rm km \cdot h^{-1}}$ .

The question states that when going against the wind ( $v = (x - y)\; {\rm km \cdot h^{-1}}$ ,) the plane travels $6111\; {\rm km}$ in $9\; {\rm h}$ . Hence, $9\, (x - y) = 6111$ .

Similarly, since the plane travels $7911\; {\rm km}$ in $9\; {\rm h}$ when travelling in the same direction as the wind ( $v = (x + y)\; {\rm km \cdot h^{-1}}$ ,) $9\, (x + y) = 7911$ .

Add the two equations to eliminate $y$ . Subtract the second equation from the first to eliminate $x$ . Solve this system of equations for $x$ and $y$ : $x = 779$ and $y = 100$ .

Hence, the speed of this plane in still air would be $779\; {\rm km \cdot h^{-1}}$ , whereas the speed of the wind would be $100\; {\rm km \cdot h^{-1}}$ .

3 0

1 year ago

What should you do to both sides to solve the following equation? t 15 t15 + 10 = 14 Subtract 14 then multiply by 15 Subtract 15

seraphim [82]

Answer:

substract 10 and multiply 10

3 0

2 years ago