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3 years ago

Solve for x 4x = 51 1. x = 204 2. x = 47 3. x = 12.75

Mathematics

1 answer:

agasfer [191]3 years ago

5 0

Answer:

#. x=12.75

Step-by-step explanation:

51/4

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Who knows how to do this ughhh I need help!

suter [353]

Answer:

$\large\boxed{\sqrt{56x^{17}}=2x^8\sqrt{14x}}$

Step-by-step explanation:

$Domain:\ x\geq0\\\\\sqrt{56x^{17}}=\sqrt{4\cdot14\cdot x^{16+1}}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt{4\cdot14\cdot x^{16}\cdot x^1}\\\\\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt4\cdot\sqrt{14}\cdot\sqrt{x^{16}}\cdot\sqrt{x}=2\cdot\sqrt{14}\cdot\sqrt{x^{8\cdot2}}\cdot\sqrt{x}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=2\cdot\sqrt{14}\cdot\sqrt{(x^8)^2}\cdot\sqrt{x}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=2\cdot\sqrt{14}\cdot x^8\cdot\sqrt{x}=2x^8\sqrt{14x}$

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3 years ago

In the figure, the measure of angle 6 is 141°. What is the measure of angle 5?

zalisa [80]

Angle 5 is 39 degrees

7 0

3 years ago

Read 2 more answers

What times what equals 225?

defon

I got 5 times 45 because I multiplied by 5 to get my answer.

4 0

3 years ago

Using the Law of Detachment, find the conclusion for the following: If two triangles are similar, then their corresponding angle

Savatey [412]

Answer:

∠ABC ≅ ∠XYZ

Step-by-step explanation:

Given: ΔABC is similar to ΔXYZ.

If two triangles are similar, then

1. the corresponding angles are congruent

2. the corresponding sides are proportional

From the options given,

AB ≅ XY is not applicable for similar triangles. Hence the option is wrong.

∠ABC ≅ ∠XYZ since ΔABC ≅ ΔXYZ

Hence the answer is ∠ABC ≅ ∠XYZ

4 0

3 years ago

What is the justification for the first step in proving the formula for factoring the sum of cubes?

Anna11 [10]

Explanation:

The formula isnt correctly written, it should state:

$a^3+b^3 = (a+b)(a^2-ab+b^2)$

You have to start from $(a+b)(a^2-ab+b^2)$ and end in a³+b³. On your first step, you need to use the distributive property.

$(a+b)(a^2-ab+b^2) = a*(a^2-ab+b^2) + b*(a^2-ab+b^2)$

This is equal to

$a*a^2-a*(ab) + a*b^2 + b*a^2-b*(ab) + b*b^2 = a^3 - a^2b + ab^2 +ba^2 -b^2a +b^3$

Note that the second term, -a²b, is cancelled by the fourth term, ba², and the third term, ab², is cancelled by the fifht term, -b²a. Therefore, the final result is a³+b³, as we wanted to.

5 0

3 years ago