Answer:
Los valores entre los cuales oscila la distancia del automóvil después de 5 horas es entre 300 metros y 400 metros.
Step-by-step explanation:
Dado que la velocidad mínima del taxi = 60 km / h, la velocidad máxima del taxi = 80 km / h
Por lo tanto, tenemos la distancia mínima cubierta después de una hora = 60 km / h × 5 h = 300 m
La distancia máxima recorrida después de una hora = 80 km / h × 5 h = 400 m, lo que da el rango de variación de la distancia recorrida entre 300 my 400 metros.
Donde, la distancia cubierta = x, tenemos
300 metros ≤ x ≤ 400 metros.
Answer:
25
Step-by-step explanation:
From the given information;
Numbers of posters that can be printed in an hour = no of impression/hour × no of plate utilized in each impression.
= 1000x
Thus, the required number of hours it will take can be computed as:

cost per hour = 125
If each plate costs $20 to make, then the total number of plate will equal to 40x
∴
The total cost can be computed as:


At C'(x) = 0




x = 25


where; x = 25

C''(x) = 1.6
Thus, at x = 25, C'' > 0
As such, to minimize the cost, the printer needs to make 25 metal plates.
x > -3 and x < 4
in interval notation

>; < - a open circle on the number line and the parenthesis ( or )
≥; ≤ - a filled-in circle on the number line and the parenthesis [ or ]
An = a1 + (n-1)*d
n = term to find = 30
a1 = first term = 20
d = common difference = 2
a30 = 20 + (30 - 1) * 2
a30 = 20 + 29 * 2
a30 = 20 + 58
a30 = 78
sn = (n (a1 + a30)) / 2
s30 = (30(20 + 78) / 2
s30 = (30(98) / 2
s30 = 2940/2
s30 = 1470 <===
Answer:
D
Step-by-step explanation: