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Phoenix [80]
2 years ago
6

If triangle RST is within Quadrant 2 and csc T = 13/12, what is the value of cotT?

Mathematics
2 answers:
zhuklara [117]2 years ago
5 0

Answer:

\boxed {cot T = -\frac{5}{12}}

Step-by-step explanation:

<u>Finding the missing side</u> :

  • x² = 13² - 12²
  • x² = 169 - 144
  • x = √25
  • x = 5

<u>Taking the cot value</u> :

  • cot T = adjacent / opposite
  • cot T = -5/12 (As cot is negative in Quadrant 2)
Marina86 [1]2 years ago
5 0

Answer:

csc T =13/12

(cot T)^2=csc^2T -1

Cot T)^2=(13/12)^2-1

(cot. T )^2=169/144-1

(cot T)^2=169-144/144

(cot T)^2=25/144

cot T =√ 25/144

cot T=5/12

where cot is negative in WE

so Cot T=-5/12

Step-by-step explanation:

please mark me as brainlest

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