Question

If triangle RST is within Quadrant 2 and csc T = 13/12, what is the value of cotT?

Answer 1

Answer:

$\boxed {cot T = -\frac{5}{12}}$

Step-by-step explanation:

Finding the missing side :

• x² = 13² - 12²
• x² = 169 - 144
• x = √25
• x = 5

Taking the cot value :

• cot T = adjacent / opposite
• cot T = -5/12 (As cot is negative in Quadrant 2)

Answer 2

Answer:

csc T =13/12

(cot T)^2=csc^2T -1

Cot T)^2=(13/12)^2-1

(cot. T )^2=169/144-1

(cot T)^2=169-144/144

(cot T)^2=25/144

cot T =√ 25/144

cot T=5/12

where cot is negative in WE

so Cot T=-5/12

Step-by-step explanation:

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