Answer:
A line is identified when you name two points on the line and draw a line over the letters. A line is a set of continuous points that extend indefinitely in either of its direction. Lines are also named with lowercase letters or a single lower case letter.
Given:
The function is

To find:
The asymptotes and zero of the function.
Solution:
We have,

For zeroes, f(x)=0.



Therefore, zero of the function is 0.
For vertical asymptote equate the denominator of the function equal to 0.


Taking square root on both sides, we get


So, vertical asymptotes are x=-4 and x=4.
Since degree of denominator is greater than degree of numerator, therefore, the horizontal asymptote is y=0.
Answer:
1/6
Step-by-step explanation:
There are 6 sides on a dice. Every time you roll you you will have one of those sides. So it is a 1 in 6 chance of you getting 4, meaning that the answer to this problem is 1/6
Line passing through point (-2, -3) with a slope of -6 is (y - (-3)) = -6(x - (-2)) => y + 3 = -6(x + 2)
Answer:
A 5 B 2 C3
Step-by-step explanation: