Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.

Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.
Therefore, the angle BKQ is equal to 180-50-45=85°.
Of course angle BKP=180-85=95°.
Hope this helps :)
Answer:
7/11
Step-by-step explanation:




Lets see!
We need to use the pythagorean theorem (a^2+b^2=c^2) to check.
So..
15^2+ 17^2 = 19^2
225+ 289= 361
Hm 225 and 289 do NOT equal 361 therefore it is NOT a right triangle.
We have two congruent trapezoids.
The formula of an area of a trapezoid:

We have:

Substitute:

Answer:

4 x p - 9 = 3 x p + 6
Hope it helped