Work = force x distance.
force = mass x acceleration
work = mass x acceleration x diastance
use acceleration of gravity in this problem
W (J) = m (kg) x a (m/s/s) x d (m)
W = 78 x 9.8 x 6
W = 4586.4
Answer: This isn't a question but the statement is quite accurate to a well thought out science lesson.
Let D be the total distance (say in meters) traveled by the train and T the time (say in seconds) it takes to do so. (Assume the train moves in a straight line in only one direction.) Then the average velocity of the train as it covers this distance is
v (ave) = D/T
We're told the train can traverse a distance of D/4 in a matter of T/2 seconds if it moves at a speed of 5 m/s. This means
D/4 = (5 m/s) (T/2)
⇒ 5 m/s = 1/2 D/T
⇒ v (ave) = D/T = 10 m/s
Answer:
Explanation:
Different measuring instruments have different level of precision . For example , our usual scale can measure upto 1 mm. Callipers can measure upto .1 mm. screw gauge can measure upto .01 mm.etc The deeper it can measure , the more precise it is. Hence screw gauge is most precise among the three.
On this basis we can say that , new caliper is less precise than old one.
Accuracy tells us about our result , how close our result is to the true measurement. It is dependent on the manner in which we take reading , So measuring methods , rather than measuring instruments , decide the accuracy of our result.
Hence we can say that the new caliper is less precise only.
The work done to "HOLD" a load of bricks at any height is zero.
Work is done only when force acts through a DISTANCE.
The work done to LIFT 30 kg of anything to 20m higher than
it already is, is
(force) · (vertical distance)
= (mass) · (gravity) · (vertical distance)
= (30 kg) · (9.8 m/s²) · (20 m)
= 5,880 joules
