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Llana [10]
4 years ago
10

Acid mine drainage is:

Physics
1 answer:
Dahasolnce [82]4 years ago
8 0

Answer:

Acid mine drainage is dissolved toxic materials wash from mines into nearby lakes and streams.

Explanation:

Acid mine drainage is the flow of acidic water with pH typically between 2 and 4, and high concentrations of other dissolved toxic materials from mines into nearby lakes and streams. It mainly occurs during metal sulfide mining, when the metal sulfide ore such as pyrite (FeS2) is exposed to water and oxygen from air to produce soluble iron and sulfuric acid.

Microorganisms, especially acidophile bacteria like Acidithiobacillus ferrooxidans grow by pyrite oxidation, i.e., oxidizing the Fe²⁺ in pyrite to Fe³⁺, which again react with pyrite and water to produce sulfuric acid. Then the acidic water flows into nearby water sources and reduces the pH value of water in those sources. As a result, heavy metals such as copper, lead, mercury, etc in other mineral ores also get dissolved into the water. The action of acidophile bacteria also increases the rate and degree of acid-mine drainage process.

The acid mine drainage causes water pollution and adversely affect the aquatic plants and animals. It also results in the contamination of drinking water, corrosion of infrastructures such as bridges, etc.

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Ann [662]

Answer:

The answer is 'D' none

Explanation:

In the figure shown we have

2Tsin(\theta )=mg\\\\\therefore T=\frac{mg}{2sin(\theta )}

From the figure we can see that

cos(\theta )=\frac{\frac{3L}{8}}{\frac{L}{2}}\\\\\therefore \theta =cos^{-1}(\frac{3}{4})\\\\sin(\theta )=\frac{\sqrt{7}}{4}

Thus value of tension be will be

T=\frac{2mg}{\sqrt{7}}

8 0
3 years ago
The crate is at rest on the incline. What can you say about the force of friction acting on the crate?A. the frictional force po
netineya [11]

Answer:

The frictional force points up the incline.

Explanation:

It is given that, the crate is at rest on the incline.  We know that the forces acting on the crate are force of gravity, normal and the force of friction. We know that the frictional force is the force that opposes the motion of an object.

In this case the crate is at rest. The crate will have static friction, that points up the incline.

So, the correct option is (A) "the frictional force points up the incline".

7 0
3 years ago
How high will a 0.345 kg rock go if thrown straight up by someone who does 111 J of work on it? Neglect air resistance.
Eddi Din [679]

To solve this problem we will apply the concepts related to energy conservation. Here we will understand that the potential energy accumulated on the object is equal to the work it has. Therefore the relationship that will allow us to calculate the height will be

W = PE

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Here,

m = mass

g = Acceleration due to gravity

h = Height

our values are,

m = 0.345 kg

g = 9.8m/s^2

W = 111J

Replacing,

W =mgh

111 = (0.345)(9.8)h

h = 32.83m

Then the height is 32.83m.

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At an amusement park, the wheelie carries passengers in a circular path of radius r = 11.2 m. If the angular speed of the wheeli
Dafna1 [17]

Answer:

(a) Tangential velocity will be 38.648 m/sec

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Explanation:

We have given radius r = 11.2 m

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v_t=\omega r=3.454\times 11.2=38.684m/sec

(b) We know that acceleration is given by

a=\frac{v^2}{r}=\frac{38.684^2}{11.2}=133.617m/sec^2

8 0
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The answer is D)Hydroponic plants are grown without soil. Nonhydroponic plants are grown in soil.

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