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AleksandrR [38]
3 years ago
7

iagara Falls is a set of very large waterfalls located on the border between New York and Ontario, Canada. Over 200,000 cubic fe

et of fast-moving water falls approximately 180 feet every second. Water at the top of the Falls possesses
Physics
1 answer:
MissTica3 years ago
3 0

Water at the top of Iagara Falls possesses gravitational potential energy
because of its height, and kinetic energy because of its motion. 

A lot of this energy is tapped off of the stream as the water falls, and is
used to generate electrical energy.

180-ft = about 54.9 meters

1 kilogram (1 liter) of water loses about

                     (1 kg) x (9.8 m/s²) x (54.9 m)

                 =      about 538 joules of potential energy,
                         while falling from the top of Iagara Falls
                         to the pool at the bottom.
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vector of zero magnitude

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In this case it moved 350 m and then returned the same 350 m, so the total displacement is zero.

If we draw the vector, one has a directional direction to the right and the other direction to the left, therefore when adding the two vectors gives a vector of zero magnitude

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Um objeto de 4cm de altura está a 30cm de um espelho côncavo, cujo raio de curvatura tem valor absoluto de 20cm.
Shkiper50 [21]

a) The distance of the image from the mirror is 15 cm

b) The size of the image is -2 cm (inverted)

Explanation:

a)

We can solve this first part of the problem by applying the mirror equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length

p is the distance of the object from the mirror

q is the distance of the image from the mirror

For a mirror, the focal length is half the radius of curvature, R:

f=\frac{R}{2}

For this mirror, R = 20 cm, so its focal length is

f=\frac{20}{2}=+10 cm (positive for a concave mirror)

Here we also know:

p = 30 cm is the distance of the object from the mirror

So, by applying the equation, we can find q:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{10}-\frac{1}{30}=\frac{1}{15} \rightarrow q = 15 cm

b)

We can solve this part by using the magnification equation:

M=-\frac{y'}{y}=\frac{q}{p}

where

y' is the size of the image

y is the size of the object

q is the distance of the image from the mirror

p is the distance of the object from the mirror

Here we have:

q = 15 cm

p = 30 cm

y = 4 cm

Solving for y', we find the size of the image:

y'=-y\frac{q}{p}=-(4)\frac{15}{30}=-2 cm

and the negative sign means that the image is inverted.

#LearnwithBrainly

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