If the distance between two objects is decreased to 1/10 of the original

2 answers:

mihalych1998 [28]3 years ago

5 0

F = GMm/r²

The force follows inverse square law.

If the distance is reduced to (1/10) of the original value,

F = GMm/(1/10r)²

F = GMm/(1/100)r<span>²

F = </span> 100* GMm/r<span>²

Hence the force is 100 times the original value.</span>

GaryK [48]3 years ago

4 0

The force of attraction between two objects is proportional to the mass of the objects and inversely proportional to the square of teh distance between them. In this casem if the distance is decreased to 1/10 of the original, then teh force of attraction increases by 100 times (10^2).

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