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zheka24 [161]
3 years ago
12

Find all real and complex roots of the equation below x^4-81=0

Mathematics
1 answer:
Pepsi [2]3 years ago
8 0

x^4-81=0 \\ (x^2-9)(x^2+9)=0\\ (x-3)(x+3)(x^2+9)=0\\ x=3 \vee x=-3 \vee x=3i \vee x=-3i

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Help please i need it fast
san4es73 [151]

Answer:

125x125

125=5x5x5

125x125=5x5x5x5x5x5=5 to the power of 6

6 0
3 years ago
Read 2 more answers
How do you Round 96,286 to the nearest thousand.
Varvara68 [4.7K]

Answer:

The correct answer is 96,000

Step-by-step explanation:

To round you look at the thousands place and there is a 9 then you look at the number to the right of it which is 2 and it is lower than 5 since it is lower than five it rounds down so the correct answer is 96,000.

HAVE A GOOD DAY!

8 0
3 years ago
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Could i please get this by today?
aleksley [76]

Answer:

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Step-by-step explanation:

Ex1: Is he earns 1/6 of his sales, then it's 1500x6, which is 9000$.

Ex2: Shown in answer.

Ex3: !60+38=198+18=236+38=312.

Ex4: :'(

Ex5: Ruby is 3 lbs less than half her mom's weight, so it would be 76x2=152, then 152-3=149.

4 0
3 years ago
The marginal profit in dollars on Brie cheese sold at a cheese store is given by Upper P prime (x )equals x (60 x squared plus 9
blondinia [14]

Answer:

Part A:

P(x)=15x^4+30x^3-50

Part B:

P(4)=$4270

Step-by-step explanation:

Part A:

In order to find the profit function P(x) we have to integrate the P'(x)

P'(x)=x(60x^2+90x)

P'(x)=60x^3+90x^2

\int\limits {p'(x)} \, dx =\int\limits {60x^3+90x^2} \, dx

P(x)=15x^4+30x^3+C

when x=0, C=-50

P(x)=15x^4+30x^3-50

Part B:

x=4

P(x)=15x^4+30x^3-50

P(4)=15*4^4+30*4^3-50

P(4)=$4270

Profit from selling 400 pounds is $4270

8 0
3 years ago
Help please I NEED TO PASS :(((((
adoni [48]

Answer:

The answer should be C

Step-by-step explanation:

I just got done calculating it and according to my calculations it should be C

5 0
3 years ago
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