Answer: 95N
Explanation:
Force necessary to stretch a spring = ?Extension of spring, e = 0.5 m
Spring constant, k = 190 N/m
Apply the formula for Hooke's law,
Force = Spring constant x extension
i.e F = ke
F = 190 N/m x 0.5 m
F = 95 N
Thus, 95 Newton of force is necessary to stretch the spring
The power required from a 75-kg patient when the treadmill is sloping at required speed is 131.58 W.
<h3>Parallel force on the patient</h3>
The parallel force on the patient is calculated as follows;
F = mg sinθ
F = (75 x 9.8) x sin(12)
F = 152.82 N
<h3>Average power required </h3>
P = FV
where;
- V is speed = 3.1 km/h = 3.1/3.6 = 0.861 m/s
F = 152.82 x 0.861
F = 131.58 W
Thus, the power required from a 75-kg patient when the treadmill is sloping at required speed is 131.58 W.
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Answer:
the si unit of electric current is Ampere .the flow of charge in a close circuit is called electric current
Answer:
The answer is 7.52 m/s².
Explanation:
To determine acceleration, N = Ma×g ÷ cos Ф
N sin Ф = ma
a = g Tan Ф m/s²
g = 9.8 m/s² and Ф = 37.5° ( angle for the velocity and gravitational force)
so, a = 9.8 × tan (37.5°)
Acceleration has to be determined in order to get the final answer.
a = 7.5198 m/s²
Answer:
The frequency of sound heard by the boy is 1181 Hz.
Explanation:
Given that,
Frequency of sound from alarm
Speed = -8.25 m/s
Negative sign show the boy riding away from the car
Speed of sound = 343
We need to calculate the heard frequency
Using formula of frequency
Where, = frequency of source
= speed of observer
= speed of source
= speed of sound
Put the value into the formula
here, source is at rest
Hence, The frequency of sound heard by the boy is 1181 Hz.