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3 years ago

An example of an object in projectile motion is

Physics

2 answers:

liubo4ka [24]3 years ago

6 0

A). The frog is the example.

Projectile motion is anything with constant horizontal velocity and accelerated vertical velocity. That's what the frog has, and he doesn't even know it.

Usimov [2.4K]3 years ago

4 0

Answer: a. a leaping frog

Explanation: In a projectile motion the object must have a certain path or trajectory with respect to a certain angle. For the leaping frog its velocity can be resolve into components having the final velocity at the highest point to be zero.

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The highest barrier that a projectile can clear is 24.7 m, when the projectile is launched at an angle of 23.0 Â° above the hori

ra1l [238]

Initial velicity Vo.

Sin(23) = 24.7 / Vo
Vo = 24.7/Sin(23)
V0 = 63.2 m/sec

4 0

3 years ago

A car traveling 36 mi/h accelerates uniformly

iren2701 [21]

First convert from mi/h to ft/s. There are 5280 ft to 1 mi, and 3600 s to 1 h, so

36 mi/h = (36 mi/h) * (5280 ft/mi) * (1/3600 h/s) = 52.8 ft/s

Let a be the acceleration of the car. The car's speed at time t is

v = 52.8 ft/s + a t

so that after 5.4 s, it attains a speed of

v = 52.8 ft/s + (5.4 s) a

Recall that

v² - u² = 2 a ∆x

where u is the car's initial velocity and ∆x is the distance it's traveled.

We have

(52.8 ft/s + (5.4 s) a)² - (52.8 ft/s)² = 2 a (595 ft)

Omitting units, this equation reduces to

(52.8 + 5.4 a)² - 52.8² = 1190 a

==> 29.16 a² - 619.76 a = 0

==> 29.16 a - 619.76 = 0

==> 29.16 a = 619.76

==> a ≈ 21.25 ft/s²

7 0

3 years ago

If m1 is 50 kg and has a velocity of 4 m/s, and m2 is 75 kg and has a velocity of -1 m/s, then what would be the final velocity

MAXImum [283]

The final velocity of object 2 is: 3 m/sec

<h3>What is the conservation of mass?</h3>

According to the rule of conservation of mass, no atoms are created or destroyed during a chemical process. Instead, the atoms combine in a variety of ways to create goods. This explains why each element has the equal amount of atoms on both sides of an equation with balanced symbols.

According to conservation of mass,

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Given that,

m₁ = 50 kg

m₂ = 75 kg

u₁ = 4 m/s

u₂ = -1 m/s

v₁ = -2 m/s

v₂ = ?

Now, putting the values,

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(50 × 4) + [75 × (-1)] = [50 × (-2)] + (75 × v₂)

or, 125 = -100 + 75 v₂

or, 75 v₂ = 225

or, v₂ = 3 m/sec.

To know more about velocity refer to:

brainly.com/question/80295

#SPJ1

6 0

1 year ago

What is the angle of reflection?

hoa [83]

I can guarantee you that it is not
C.the angle that the incident ray makes with a line drawn perpendicular to the reflecting surface I hope this somewhat helps

4 0

3 years ago

A rock with a mass of 16 kilograms is put aboard an airplane in New York City and flown to Boston. How much work does the gravit

Law Incorporation [45]

The work done by the gravitational field of the earth on the rock is 9.998 x 10⁸ J.

The given parameter include:

the mass of the object, m₁ = 16 kg

Note: the mass of the earth, m₂ = 5.972 x 10²⁴ kg

The work done by the gravitational field of the earth is given as;

Work done = gravitational force (F) x radius of the earth (R)

$Work \ done = \frac{Gm_1m_2}{R^2} \times R\\\\Work \ done = \frac{Gm_1m_2}{R} \\\\where;\\\\R \ is \ the \ radius \ of \ the \ earth = 6,378 \ km = 6,378,000 \ m\\\\G \ is \ the \ universal \ gravitation \ constant = 6.674 \times 10^{-11} Nm^2/kg^2\ \\\\Work \ done = \frac{(6.674 \times 10^{-11} ) \times (5.972\times 10^{24}) \times (16)}{6,378,000 } \\\\Work \ done = 9.998 \times 10^{8} \ J$

Therefore, the work done by the gravitational field of the earth on the rock is 9.998 x 10⁸ J.

To learn more about work done by gravitational field of the earth visit: brainly.com/question/13934028

7 0

3 years ago