Initial velicity Vo.
Sin(23) = 24.7 / Vo
Vo = 24.7/Sin(23)
V0 = 63.2 m/sec
First convert from mi/h to ft/s. There are 5280 ft to 1 mi, and 3600 s to 1 h, so
36 mi/h = (36 mi/h) * (5280 ft/mi) * (1/3600 h/s) = 52.8 ft/s
Let <em>a</em> be the acceleration of the car. The car's speed at time <em>t</em> is
<em>v</em> = 52.8 ft/s + <em>a</em> <em>t</em>
so that after 5.4 s, it attains a speed of
<em>v</em> = 52.8 ft/s + (5.4 s) <em>a</em>
Recall that
<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>
where <em>u</em> is the car's initial velocity and ∆<em>x</em> is the distance it's traveled.
We have
(52.8 ft/s + (5.4 s) <em>a</em>)² - (52.8 ft/s)² = 2 <em>a</em> (595 ft)
Omitting units, this equation reduces to
(52.8 + 5.4 <em>a</em>)² - 52.8² = 1190 <em>a</em>
==> 29.16 <em>a</em>² - 619.76 <em>a</em> = 0
==> 29.16 <em>a</em> - 619.76 = 0
==> 29.16 <em>a</em> = 619.76
==> <em>a</em> ≈ 21.25 ft/s²
The final velocity of object 2 is: 3 m/sec
<h3>What is the conservation of mass?</h3>
According to the rule of conservation of mass, no atoms are created or destroyed during a chemical process. Instead, the atoms combine in a variety of ways to create goods. This explains why each element has the equal amount of atoms on both sides of an equation with balanced symbols.
According to conservation of mass,
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Given that,
m₁ = 50 kg
m₂ = 75 kg
u₁ = 4 m/s
u₂ = -1 m/s
v₁ = -2 m/s
v₂ = ?
Now, putting the values,
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(50 × 4) + [75 × (-1)] = [50 × (-2)] + (75 × v₂)
or, 125 = -100 + 75 v₂
or, 75 v₂ = 225
or, v₂ = 3 m/sec.
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I can guarantee you that it is not
C.<span>the angle that the incident ray makes with a line drawn perpendicular to the reflecting surface I hope this somewhat helps</span>
The work done by the gravitational field of the earth on the rock is 9.998 x 10⁸ J.
<u>The given parameter include:</u>
the mass of the object, m₁ = 16 kg
Note: the mass of the earth, m₂ = 5.972 x 10²⁴ kg
- The work done by the gravitational field of the earth is given as;
Work done = gravitational force (F) x radius of the earth (R)

Therefore, the work done by the gravitational field of the earth on the rock is 9.998 x 10⁸ J.
<u>To learn more about work done by gravitational field of the earth visit</u>: brainly.com/question/13934028