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4 years ago

Which of the following is an example of conduction?

1 answer:

7 0

the answer was C because Heat is transferred by conduction when a hot object is in direct contact with a cold object. So, a metal spoon becoming warm when placed in a cup of hot tea is an example of conduction because the spoon gains heat by being in direct contact with the hot tea.

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A(n) ________________________ is a molecule that is soluble in both polar and nonpolar solvents.

Alex

Answer: ethanol which will dissolve in both water (a polar solvent) and gasoline (a non-polar solvent)

Explanation:

3 0

3 years ago

Can magnets pick up all kinds of materials?

My name is Ann [436]

Well it depends it has to be some kind of metal material if not then it will not pick it up Hope this helps:)

7 0

3 years ago

Consider a wire of a circular cross-section with a radius of R = 3.17 mm. The magnitude of the current density is modeled as J =

Sloan [31]

Answer:

The current is $I = 8.9 *10^{-5} \ A$

Explanation:

From the question we are told that

The radius is $r = 3.17 \ mm = 3.17 *10^{-3} \ m$

The current density is $J = c\cdot r^2 = 9.00*10^{6} \ A/m^4 \cdot r^2$

The distance we are considering is $r = 0.5 R = 0.001585$

Generally current density is mathematically represented as

$J = \frac{I}{A }$

Where A is the cross-sectional area represented as

$A = \pi r^2$

=> $J = \frac{I}{\pi r^2 }$

=> $I = J * (\pi r^2 )$

Now the change in current per unit length is mathematically evaluated as

$dI = 2 J * \pi r dr$

Now to obtain the current (in A) through the inner section of the wire from the center to r = 0.5R we integrate dI from the 0 (center) to point 0.5R as follows

$I = 2\pi \int\limits^{0.5 R}_{0} {( 9.0*10^6A/m^4) * r^2 * r} \, dr$

$I = 2\pi * 9.0*10^{6} \int\limits^{0.001585}_{0} {r^3} \, dr$

$I = 2\pi *(9.0*10^{6}) [\frac{r^4}{4} ] | \left 0.001585} \atop 0}} \right.$

$I = 2\pi *(9.0*10^{6}) [ \frac{0.001585^4}{4} ]$

substituting values

$I = 2 * 3.142 * 9.00 *10^6 * [ \frac{0.001585^4}{4} ]$

$I = 8.9 *10^{-5} \ A$

5 0

4 years ago

A substance sample has a Mass of 45.0 g, and the Data Safety

marishachu [46]

The volume of the sample is 48.39 cm³.

<h3 /><h3>What is volume?</h3>

The term volume refers to the amount of three-dimensional space taken up by an item or a closed surface

To calculate the volume of the sample, we use the formula below

Formula:

D = m/v
v = m/D................ Equation 1

Where:

m = Mass of the smaple
D = Density of the sample
v = Volume of the sample.

From the question,

Given:

m = 45 g
D = 0.93 g/cm³

Substitute these values into equation 1

v = 45/0.93
v = 48.39 cm³

Hence, the volume of the sample is 48.39 cm³.

Learn more about volume here:brainly.com/question/27710307

#SPJ1

8 0

2 years ago

Does anyone know this?

Radda [10]

Answer:

999990900

Explanation:

lololo

8 0

3 years ago