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viktelen [127]
3 years ago
13

2/3x + 2= 21/3 solve for x a. 0 b. 1/2 c -2 d. 2

Mathematics
1 answer:
Helen [10]3 years ago
8 0

Answer:

x = 7.5

Step-by-step explanation:

2/3x + 2= 21/3

Subtract 2 from each side

2/3x + 2-2= 21/3-2

2/3x = 21/3 - 6/3

2/3x =15/3

2/3x = 5

Multiply each side by 3/2 to isolate x

2/3x * 3/2 = 5 *3/2

x = 15/2

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What value of b will cause the system to have an infinite number of solutions?
irga5000 [103]

b must be equal to -6  for infinitely many solutions for system of equations y = 6x + b and -3 x+\frac{1}{2} y=-3

<u>Solution: </u>

Need to calculate value of b so that given system of equations have an infinite number of solutions

\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}

Let us bring the equations in same form for sake of simplicity in comparison

\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}

Now we have two equations  

\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}

Let us first see what is requirement for system of equations have an infinite number of solutions

If  a_{1} x+b_{1} y+c_{1}=0 and a_{2} x+b_{2} y+c_{2}=0 are two equation  

\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}} then the given system of equation has no infinitely many solutions.

In our case,

\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}

 As for infinitely many solutions \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}

\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}

Hence b must be equal to -6 for infinitely many solutions for system of equations y = 6x + b and  -3 x+\frac{1}{2} y=-3

8 0
3 years ago
Is x=-2 a solution for the equation below?
Misha Larkins [42]

Answer:

no

Step-by-step explanation:

-7+x^2-3x      =       9+x-10

-7+(-2)^2-3*(-2)                   9+(-2)-10

-7+4+6                                9-12

3                   >                      -3

if we substitute -2 to x, answer is not equal

3 0
3 years ago
Read 2 more answers
Write an equation that passes through the point (1, 3) and is perpendicular to x – 2y = -8.
Umnica [9.8K]

Answer:

y = -2x + 5

Step-by-step explanation:

Given:

Passes through point (1, 3)

Perpendicular to x – 2y = -8

Solve:

x – 2y = -8

y = 1/2x + 4

The slope is m = 1/2

The slope of the perpendicular line is the inverse of the slope of the original equation.

The slope of the inverse equation is m = -2.

Making an inverse equation of y = -2x + a

Find a:

Use point, (1, 3) where (x, y):

3 = (-2)*(1) + a

a = 5

y = -2x + 5

4 0
3 years ago
Read 2 more answers
What is the following number in decimal form?
aleksley [76]
8.8 because you need to multiply 1.68 by 10 which is 16.8-8=8.8

6 0
3 years ago
Math school is selling tickets to a play on the first day of ticket sales the school sold two adult tickets and three students t
Illusion [34]

Answer: the cost of an adult ticket is $9.

The cost of a child's ticket is $13

Step-by-step explanation:

Let x represent the price of one adult ticket.

Let y represent the price of one student ticket.

On the first day of ticket sales, the school sold two adult tickets and three students tickets for a total of $57. It means that

2x + 3y = 57- - - - - - - - - -1

The school took and $70 on the second day by selling two adult tickets and four student tickets. It means that

2x + 4y = 70- - - - - - - - - -2

Subtracting equation 2 from equation 1, it becomes

- y = - 13

y = 13

Substituting y = 13 into equation 1, it becomes

2x + 3 × 13 = 57

2x + 39 = 57

2x = 57 - 39 = 18

x = 18/2

x = 9

8 0
3 years ago
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