Question

Let R = {0, 1, 2, 3} be the range of h (x ) = x - 7. The domain of h inverse is

Answer 1

Hello,


As h(x) is a bijection,
range(h(x))=dom(h^(-1)(x))={0,1,2,3}

Answer C

Answer 2

Answer{1,2,3}

Step-by-step explanation:

Given

Range of h(x)={0,1,2,3}

h(x)=x-7

thus domain of h(x)=[7,10]

because for x=7 h(x)=0

x=8 h(x)=1

x=9 h(x)=2

x=10 h(x)=3

inverse of h(x) is g(x) is given by

$g(x)=\frac{1}{x}-7$

Therefore domain of g(x) is range of h(x)

but it will not be defined for x=0

therefore its domain is {1,2,3}