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Yuki888 [10]
3 years ago
15

Forrest spills some acid on the lab floor. He notifies his teacher and begins to look for baking soda to neturalize the acid on

the floor. Who should be notified next ?
Chemistry
2 answers:
Romashka [77]3 years ago
8 0

Explanation:

Since, acid is spilled on the lab floor so, first of all the teacher must be notified about it. As teacher can better tell you what should be done in such a case.

At the same time, rest of the students present in the lab must be notified about it so that no one can accidentally step onto the acid otherwise it might cause a serious injury to anyone.

Thus, we can conclude that rest of the students or classmates should be notified next in the given situation.

gregori [183]3 years ago
7 0
His classmates should be notified next
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blagie [28]

Answer:

if i had to guess it would be D

Explanation:

Sorry if im wrong, but i wouldnt have any liquid on atleast one of them so i can compare and contrast the other coins to the regular 1p coins

3 0
3 years ago
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What does the group number of element 114 have to do with its stability?
zhenek [66]

Answer:

Super-heavy elements like 114 usually only exist for fractions of a second. ... The physicists called these magic numbers the “island of stability”, because the elements with the numbers cluster together on the periodic table, flanked on all sides by ephemeral elements that dissipate in nanoseconds.

8 0
3 years ago
1. Calculate the energy of a photon with a frequency of 3x1015 Hz.<br> ?????
Afina-wow [57]

Answer:

1.99 x 10⁻¹⁸J

Explanation:

Given parameters:

Frequency of the wave  = 3 x 10¹⁵Hz

Unknown:

Energy of the photon  = ?

Solution:

To solve this problem, we use the expression below;

     E  = hf

Where E is the energy, h is the Planck's constant and f is the frequency

Now insert the parameters and solve for E;

     E  = 6.63 x 10⁻³⁴ x 3 x 10¹⁵ = 19.9 x 10⁻¹⁹J or 1.99 x 10⁻¹⁸J

6 0
3 years ago
If a gas furnace releases 420 kcal of heat energy, what is the energy in kilojoules? (1 cal = 4.184 J)
Igoryamba
Answer:
The furnace releases 1757280 J 

Explanation:
We will do the conversion on two steps:
1- convert the kcal to cal
2- convert the cal to J

Step 1: converting kcal to cal
1 kcal is equivalent to 1000 cal. Therefore:
420 kcal is equivalent to 420*1000 = 420000 cal

Step 2: converting cal to J
We are given that:
<span>1 cal = 4.184 J
</span>Therefore:
420000 cal is equivalent to 420000 * 4.184 = 1757280 J 

Hope this helps :)
8 0
4 years ago
Determine the expected diffraction angle for the first-order diffraction from the (111) set of planes for FCC nickel (Ni) when m
faust18 [17]

Answer:

56°

Explanation:

First calculate a:

a=2 R \sqrt{2}=2(0.1246) \sqrt{2}=0.352 \mathrm{nm}

The interplanar spacing can be calculated from:

d_{111}=\frac{a}{\sqrt{1^{2}+1^{2}+1^{2}}}=\frac{0.352}{\sqrt{3}}=0.203 \mathrm{nm}

The diffraction angle is determined from:

\sin \theta=\frac{n \lambda}{2 d_{111}}=\frac{1(0.1927)}{2(0.2035)}=0.476

Solve for \theta

\theta=\sin ^{-1}(0.476)=28^{\circ}

The diffraction angle is:

2 \theta=2\left(28^{\circ}\right)=56^{\circ}

4 0
3 years ago
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