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juin [17]
3 years ago
13

What change would you expect on the rate of theSN2 reaction of 1-iodo-2-methylbutane withcyanide ion if the nucleophile concentr

ation isunchanged and the alkyl halide concentration isdoubled?
What change would you expect on the rate of thereaction of ethanol with 2-iodo-2-methylbutane ifthe nucleophile concentration is halved by adding diethylether as an inert solvent and the alkyl halideconcentration is unchanged?
Chemistry
1 answer:
Ivenika [448]3 years ago
6 0

Answer:

The reaction rate of the both questions remain unchanged.

Explanation:

      For question 1:  The reaction 1-iodo -2- methylbutane with cyanide ion is an SN2 reaction because the Alkyl halide is a primary alkyl halide. The rate of reaction is dependent on concentration of the nucleophile and the alkyl halide at the same. For the rate of reaction to be affected (increased or decreased), the concentration of nucleophile and the alkyl halide have to be altered.

      For question 2: The reaction of 2-iodo -2- methylbutane with ethanol is an SN1 reaction because the Alkyl halide is a tertiary alkyl halide. There are two-step reaction mechanism in this reaction. The first step is the rate determining step which determines the extent of the reaction and hence the rate of reaction. For the rate of reaction to be affected (increased or decreased), the concentration of the Alkyl halide alone will be altered. The rate of reaction is independent of the concentration of the nucleophile.

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The solubility of calcium sulfate at 30°c is 0.209 g/100 ml solution. calculate its ksp.
inessss [21]
Answer is: Ksp for calcium sulfate is 2.36·10⁻⁴.
Balanced chemical reaction (dissociation):
CaSO₄(s) → Ba²⁺(aq) + SO₄²⁻(aq).
m(CaSO₄) = 0.209 g.
n(CaSO₄) = m(CaSO₄) ÷ M(CaSO₄).
n(CaSO₄) = 0.209 g ÷ 136.14 g/mol.
n(CaSO₄) = 0.00153 mol.
s(CaSO₄) = n(CaSO₄) ÷ V(CaSO₄).
s(CaSO₄) = 0.00153 mol ÷ 0.1 L = 0.0153 M.
Ksp = [Ca²⁺] · [SO₄²⁻].
[Ca²⁺] = [SO₄²⁻] = s(CaSO₄).
Ksp = (0.0153 M)² = 2.36·10⁻⁴.
8 0
3 years ago
Copper has a density of 8.96 g/cm3. If a thin sheet of copper measures 5.5 cm by 5.5 cm and has a mass of 12.96 g, what is its t
balandron [24]

Thickness of cooper sheet is 0.048 cm (Approx.)

Given that;

Density of copper = 8.96 g/cm³

Measures of copper sheet = 5.5 cm × 5.5 cm

Mass of of copper sheet = 12.96 gram

Find:

Thickness of cooper sheet

Computation:

Volume = Mass / Density

Volume of cooper = 12.96 / 8.96

Volume of cooper = 1.4464

Volume of cooper = 1.45 cm³ (Approx.)

Volume of cooper sheet = 5.5 cm × 5.5 cm x Thickness

5.5 cm × 5.5 cm x Thickness = 1.45

Thickness of cooper sheet = 0.04793

Thickness of cooper sheet = 0.048 cm (Approx.)

Learn more:

brainly.com/question/24235924?referrer=searchResults

8 0
3 years ago
I don't know how to do this can I get the answers plz it's due in 1 hour
katrin [286]
Okay, so even if I just gave you the answers, your teacher needs work on it too so it'll be easier/better if I just explain how to do it.
Basically, both sides need to have the same number of molecules. To do this, we make charts. This is the first side of number one:
Na - 1
Mg- 1
F - 2
The subscript gives F two molecules, and the other ones only each have one. This is the second side:
Na- 1
Mg- 1
F- 1
So they're not equal. To fix this, we add coefficients. These are numbers that are going to appear in the front of each compound/element and changes the number of molecules of the WHOLE compound/element. We need two F on the second side, so we'll put a coefficient of 2 in front of NaF. The new chart for the second side is this:
Na- 2
Mg- 1
F- 2
Now we've fixed the F, but now Na is off! So let's go to the first side again and see what we can do. We can put a 2 in front of the Na. The new chart is this:
Na- 2
Mg -1
F- 2
Now both sides are the same. The full new equation is:
2Na + MgF(sub2) = 2NaF + Mg
Basically, do this for all of them. Feel free to ask more questions.
4 0
3 years ago
Read 2 more answers
D5W is a solution used as an intervenous fluid.It is 5.0% by mass solution of the dextrose (C6H12O6) in water. if the density of
Alona [7]

Answer:

0.29 mol/L

Explanation:

Its density is 1.029 g/ml so in a liter (1000 mL) there is 1029 g of solution, but only 5% is dextrose.

0.05x1029=51.45

So in a liter of D5W solution there is 51.45 g of dextrose.

Dextrose molar mass iss 180.156 g/mol, so in 51.45 g of dextrose there is

51.45/180.156=0.29 mol

In one liter of solution there is 0.29 mol of dextrose, so the molarity of such solution is 0.29 mol/L.

6 0
3 years ago
What is the nuclear binding energy in joules for an atom of lithium?
deff fn [24]
Answer:

<span>5.1012⋅<span>10<span>−12</span></span>J t</span>he idea here is that you need to use the mass of a single proton and the mass of a single neutron to calculate the mass of a lithium-6 nucleus, then use the measured value to find its mass defect.

5 0
3 years ago
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