Answer:
Cl⁻, Na⁺, OH⁻
Explanation:
The titration is:
CuCl₂(aq) + 2 NaOH(aq) → Cu(OH)₂(s) + 2 NaCl(aq)
In solution, before the reaction, the ions are Cu²⁺ and Cl⁻. The addition of NaOH (Na⁺ + OH⁻) produce the precipitation of Cu²⁺ forming Cu(OH)₂(s). When you reach the equivalence point, there is no Cu²⁺ because precipitates completely. All OH⁻ ions reacts when are added but when Cu²⁺ is finished, excess OH⁻ ions still in solution helping to detect the equivalence point.
Thus, ions present after the equivalence point are:<em> Cl⁻, Na⁺</em> (Don't react, spectator ions), and <em>OH⁻</em>.
Answer:
C) Liquids and gases
Explanation:
<em>The correct answer would be liquids and gases.</em>
<u>The molecules of liquids and gases move randomly when held in a container. The random movement causes a collision between the molecules of the liquids/gases and between the walls of the container, creating pressure in the process. </u>This is unlike the molecules of solids that vibrate about fixed positions.
Hence, the correct option is C.
I search it in the internet so here you go
Answer:
0.225M
Explanation:
Step 1:
Data obtained from the question. This includes:
Volume of the stock solution (V1) = 125mL
Molarity of the stock solution (M1) = 0.90 M
Volume of the diluted solution (V2) = 125 + 375 = 500mL
Molarity of the diluted solution (M2) =..?
Step 2:
Determination of the molarity of the diluted solution.
This is obtained by using the dilution formula as follow:
M1V1 = M2V2
0.9 x 125 = M2 x 500
Divide both side by 500
M2 = (0.9 x 125) /500
M2 = 0.225M
Therefore, the molarity of the diluted solution is 0.225M
