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MariettaO [177]
3 years ago
8

Plz help!! If the mass of an object is 44 kilograms and its velocity is 10 meters per second east, how much Kinetic Energy does

it have? A. 0.44 Joules B. 2,200 Joules C. 220 Joules D. 4,400 Joules E. 440 Joules
Physics
1 answer:
stellarik [79]3 years ago
4 0
KE = 1/2 * m * v^2
m = 44
v = 10

KE = 1/2 * 44 * (10)^2
KE = 22 * 100 = 2200 J or B
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Unbalanced because if it is pushing then stopping, that means that it is unbalanced.

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3 years ago
Two 75 W (120 V) lightbulbs are wired in series, then the combination is connected to a 120 V supply. Part A How much power is d
Elenna [48]

Answer:

<em>300 W</em>

<em></em>

Explanation:

power of each bulb P = 75 W

voltage in the circuit = 120 V

we know that electrical power P = IV    ....1

and V = IR

we can also say that I = V/R

substituting for I in  equation 1, we have

P = V^{2}/R    ....2

The total total power in the circuit = 75 x 2 = 150 W

from equation 2, we have

150 = 120^{2} /R

R = 120^{2}/150 = 96 Ω    this is the resistance of the whole circuit.

This resistance is due to the two light bulbs, for each light bulb since they are arranged in series

R = 96/2 = 48 Ω

From P =  V^{2}/R  

for each light bulb, power is

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8 0
3 years ago
A 1 900-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 4.00 m before coming into contact
Leno4ka [110]

Answer:

471392.4 N

Explanation:

From the question,

Just before contact with the beam,

mgh = Fd.................... Equation 1

Where m = mass of the beam, g = acceleration due to gravity, h = height. F =  average Force on the beam, d = distance.

make f the subject of the equation

F = mgh/d................ Equation 2

Given: m = 1900 kg, h = 4 m, d = 15.8 = 0.158 m

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3 years ago
Step by step process on how to solve this problem
rusak2 [61]

<u>Step-1:</u>  Remember or look up the formula for the force of gravity between two objects.    F = G · m₁ · m₂ / R²

<u>Step-2:</u>  Remember or look up the value of G.<em> </em> G = 6.67 x 10⁻¹¹ m³·kg/s²

<u>Step-3: </u> Write the numbers you know into the formula.

(1.989 x 10²⁰ Newtons) =

(6.67 x 10⁻¹¹ mtr³·kg/s²) · (5.9742 x 10²⁴ kg) · (moon mass) / (3.84 x 10⁸ mtr)²

<u>Step-4:</u>  Sit back, relax, take your time, look this mess over, carefully, end-to-end, and decide how to solve it for (moon mass) .

<u>Step-5:</u> Divide each side by (6.67x10⁻¹¹mtr³·kg/s²)·(5.9742x10²⁴kg)/(3.84x10⁸mtr)²:

Moon mass =

(1.989x10²⁰ Newtons)·(3.84x10⁸ mtr)²/(6.67x10⁻¹¹ mtr³·kg/s²)·(5.9742x10²⁴ kg)

<u>Step-6: </u> Crunch the numbers.  Be careful to KEEP all the units as you go along. When you're done, the units of your answer will be the first instant indication if you made a mistake.  You're looking for the MASS of the moon.  If the answer doesn't have units of 'kg', then that'll be an immediate red flag, telling you that there's been a mistake somewhere.

Moon mass =

(1.989x10²⁰ Newtons)·(3.84x10⁸ mtr)²/(6.67x10⁻¹¹ mtr³·kg/s²)·(5.9742x10²⁴ kg)

Collect the numbers, and collect the units:

Moon mass = (1.989x10²⁰ · (3.84x10⁸)² / (6.67x10⁻¹¹ · 5.9742x10²⁴)

(kg-mtr/s² · mtr²)/(mtr³·kg/s² · kg)

Moon mass = (1.989 · 3.84² x 10³⁶) / (6.67 · 5.9742 x 10¹³)

(kg-mtr/s² · mtr²)/(mtr³·kg/s² · kg)

Moon mass = 0.736 x 10²³ kg

Moon mass = 7.36 x 10²² kg

<u>Step 7: </u> Look it up in a book or online.  See if you're anywhere close.

When I search "moon mass" on Floogle, the first hit says

" 7.348 x 10²² kg " .

yay !  I'm satisfied.

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3 years ago
A clay pot at room temperature is placed in a kiln, and the pot\'s temperature doubles. how much more heat per second is the pot
xeze [42]

Answer:

16

Explanation:

If we treat the pot as a black body, then:

q = σ T⁴ A,

where q is the heat per second radiated,

σ is the Stefan-Boltzmann Constant,

T is the absolute temperature,

and A is the surface area.

If the absolute temperature doubles, then q increases by a factor of 2⁴ = 16.

7 0
3 years ago
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