Answer:
θ = 4.092 °
Explanation:
Given that
Initial Angular speed ,ωi = 0.76 rad/s
Final angular speed ,ωf= 2.96 rad/s
The angular acceleration ,α = 1 rad/s²
We know that
ωf² = ωi ²+ 2 α θ
θ=Angle rotates
2.96² = 0.76²+ 2 x 1 x θ
Therefore the angle rotates by machine part will be 4.092 degrees.
θ = 4.092 °
Answer:
It is easy to imagine representing a narrow beam of light by a collection of parallel arrows—a bundle of rays. As the beam of light moves from one medium to another, reflects off surfaces, disperses, or comes to a focus, the bundle of rays traces the beam's progress in a simple geometrical manner.
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Answer:
The acceleration of a 2 kg box acted on by a net force of 2 N is solved by using Newton’s second law of motion in the form acceleration = F_net / mass. Since the mass of the box is 2 kg and the net force is 2 N, the acceleration of the 2 kg box is 1 m/s^2.
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