Solid is one of the three main states of matter, along with liquid and gas. Matter is the "stuff" of the universe, the atoms, molecules and ions that make up all physical substances. In a solid, these particles are packed closely together and are not free to move about within the substance.
Acceleration is defined as the rate of change of velocity, which, simply put, is a mouthful to describe how fast something speeds up, slows down, or turns. The equation for acceleration is
a = Δv / Δt,
or your final velocity - your starting velocity, then divided by the amount of time. It can also be expressed as
a = (Vf - Vi) / t,
Where Vf is your final velocity, Vi is your initial velocity, and t is the time traveled.
The question gives us that the helicopter moves from a starting velocity of 30 m/s to a final velocity of 40 m/s in the span of 5 seconds. This means we can fill in the variables to the equation, where
Vf = 40,
Vi = 30, and
t = 5.
Plug these known variables into the original equation, and we get
a = (Vf - Vi) / t = (40 - 30) / 5.
From here, the answer comes down to 10 / 5, or 2 m/s^2.
Hope this helps! If you have any questions, don't hesitate to ask :D
Answer:
+9.8m/s^2
Explanation:
The rate of gravity of the object is constant thriughout the surface of the earth.
For falling object, the rate of gravity is positive since the body is coming down (falling)
The rate of gravity is negative if the body is going up
The constant value for acceleration due to gravity is 9.8m.s^2
Since the object is falling, hence the acceleration due to gravity is positive.
Rate of gravity working on the object will be +9.8m/s^2
Frequency and wavelength are two variables which are
indirectly proportional.
They are related in the following equation:
f = c / w
Where,
<span>f = frequency c =
speed of light w = wavelength</span>
Since c is constant, we can equate condition 1 and
condition 2:
f1 w1 = f2 w2
When w2 = 3 w1, then f2 becomes:
261.63 w1 = f2 (3 w1)
Cancelling w1:
f2 = 261.63 / 3
<span>f2 = 87.21 Hz</span>
Answer:

Explanation:
As we know that if a charge q is distributed uniformly on the line then its linear charge density is given by

now the electric field due to long line charge at a distance d from it is given as


now the force on the other charge in this electric field is given as

