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Elden [556K]
3 years ago
14

Carbon-14 has a half life of 5730 years. Consider a sample of fossilized wood that when alive would have contained 24g of C-14 i

t now contains 1.5g. How old is the sample
Physics
1 answer:
kirza4 [7]3 years ago
6 0

Answer:

5732 years

Explanation:

hope it helps, if not im sorry

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How many hydrogens are in 3 molecules of H20?
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1 atom of oxygen

2 atoms of hydrogen in each molecule

Each water molecule contains 3 atoms making the H2O formula

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A museum curator moves artifacts into place on various different display surfaces. If the curator moves a 145 kg aluminum sculpt
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Question #6
Novay_Z [31]

The two points on a periodic wave in a medium are said to be in phase if they have the same amplitude and are moving in the same direction.

Option 4.

Explanation:

A periodic wave is termed for waves which flow in a repetition pattern in a given time scale. Periodic wave can also be termed as a transverse wave. So a transverse wave have various crests and troughs. The two successive crests and two successive troughs are said to be in phase with each other.

Thus, for a periodic wave in a medium, the in phase can be obtained in two points which have the same amplitude and are moving in the same direction.

As amplitude is a scalar quantity and so direction should be taken into consideration for making the points related to successive crests only in phase with themselves. Also this also relates the points related to successive troughs to be in phase with each other. But a crest and a trough will not be in phase with each other.

Thus, option 4, that is the two points on a periodic wave in a medium are said to be in phase if they have the same amplitude and are moving in the same direction.

4 0
3 years ago
Daniel steps on the gas pedal of his car, and the engine increases its performance from zero to
RSB [31]

Answer

The frequency and the period are 45 cycles/second and 0.023 seconds

Explanation:

The frequency of the engine is given by :

f=\dfrac{rpm}{60}

We have, the engine increases its performance from zero to 2700 rpms.

Frequency,

f=\dfrac{2700}{60}\ \text{cycles per second}\\\\f=45\ \text{cycles per second}

The time period of the engine is given by :

T = f/f

So,

T=\dfrac{1}{45}\ s\\\\T=0.023\ s

Hence, the required frequency and the period are 45 cycles/second and 0.023 seconds respectively.

6 0
3 years ago
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