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Nataly_w [17]
3 years ago
7

Rationalize the denominator of the fraction and enter the new denominator below.8/2-√12

Mathematics
2 answers:
Studentka2010 [4]3 years ago
8 0
\frac{8}{2-\sqrt{12}}=\frac{8}{2-\sqrt{4\cdot3}}=\frac{8}{2-2\sqrt3}=\frac{8}{2(1-\sqrt3)}=\frac{4}{1-\sqrt3}\\\\\frac{4}{1-\sqrt3}\cdot\frac{1+\sqrt3}{1+\sqrt3}=\frac{4(1+\sqrt3)}{1^2-(\sqrt3)^2}=\frac{4(1+\sqrt3)}{1-3}=\frac{4(1+\sqrt3)}{-2}=-2(1+\sqrt3)}\\\\=-2-2\sqrt3



if\ \frac{8}{2}-\sqrt{12}=4-\sqrt{4\cdot3}=4-2\sqrt3
MakcuM [25]3 years ago
7 0
\frac{8}{2-\sqrt{12}}\\
\frac{8(2+\sqrt{12})}{4-12}=\\
\frac{8(2+\sqrt{12})}{-8}=\\
-(2+\sqrt{12}})=\\
-2-\sqrt{12}=\\-2-2\sqrt3

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Answer:

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Hey there! I'm happy to help!

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We find the difference between the y-values.

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We're gonna try using the AC method first.

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Split the middle term.

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