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Korvikt [17]
4 years ago
13

An automobile traveling at the rate of 30 ft/sec is approaching an intersection. When the automobile is 120 feet from the inters

ection, a truck traveling at the rate of 40 ft/sec crosses the intersection. The automobile and the truck are on roads that are at right angles to one another. How fast are the automobile and the truck separating 2 seconds after the truck leaves the intersection?

Mathematics
1 answer:
Trava [24]4 years ago
4 0

Answer:

Distance between automobile and the truck is 100 feet.

Step-by-step explanation:

Speed of the automobile towards the intersection = 30 ft per sec

Speed of the truck that crosses the intersection = 40 ft per sec.

Automobile is 120 feet apart when the truck passes through the intersection.

After 2 seconds distance traveled by the automobile = Speed × time

= 30 × 2

= 60 feet

So the distance of the automobile from the intersection = 120 - 60

= 60 feet

Distance traveled by truck in 2 seconds = 40 × 2

= 80 feet

Now distance between them can be calculated by Pythagoras theorem

Distance = \sqrt{(60)^{2}+(80)^{2}}

= \sqrt{3600+6400}

= \sqrt{10000}

= 100 feet

Therefore, after 2 seconds distance between the truck and the automobile will be 100 feet.

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Answer:

Step-by-step explanation:

Given that a professor sets a standard examination at the end of each semester for all sections of a course. The variance of the scores on this test is typically very close to 300.

H_0: s^2 = 300\\H_a: s^2 \neq 300

(Two tailed test for variance )

Sample variance =480

We can use chi square test for testing of hypothesis

Test statistic = \frac{(n-1)s^2}{\sigma^2} \\=62.4

p value = 0.0100

Since p <0.05 our significance level, we reject H0.

The sample variance cannot be claimed as equal to 300.

5 0
3 years ago
Help me solve this question please for 10 points
ankoles [38]

Answer: D for the first one and B for the second

Step-by-step explanation:

3 0
3 years ago
What is the value of 3 to the 2 power +5 times+25?
tester [92]

Answer:


Step-by-step explanation:

3(3)^2 + 5(3) + 25

3*3 = 9, 5*3 = 15

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27 + 15 + 25 = 67

7 0
3 years ago
a square garden has a diagonal of 12 m. What is the perimeter of the garden? Express in simplest radical form
lianna [129]

Answer:

The perimeter of the garden, in meters, is 24\sqrt{2}

Step-by-step explanation:

Diagonal of a square:

The diagonal of a square is found applying the Pythagorean Theorem.

The diagonal of the square is the hypothenuse, while we have two sides.

Diagonal of 12m:

This means that d = 12, side s. So

s^2 + s^2 = 12^2

2s^2 = 144

s^2 = \frac{144}{2}

s^2 = 72

s = \sqrt{72}

Factoring 72:

Factoring 72 into prime factors, we have that:

72|2

36|2

18|2

9|3

3|3

1

So

72 = 2^{3}*3^{2}

So, in simplest radical form:

s = \sqrt{72} = \sqrt{2^{3}*3^{2}} = \sqrt{2^3}*\sqrt{3^2} = 2\sqrt{2}*3 = 6\sqrt{2}

Perimeter of the garden:

The perimeter of a square with side of s units is given by:

P = 4s

In this question, since s = 6\sqrt{2}

P = 4s = 4*6\sqrt{2} = 24\sqrt{2}

The perimeter of the garden, in meters, is 24\sqrt{2}

5 0
3 years ago
If the function 5x+y=1 has the domain (-2,1,6) then what is the corresponding range?
zysi [14]

The corresponding range of the domain is (11, -4, -29)

<h3>How to determine the range?</h3>

The function is given as:

5x + y = 1

Make y the subject

y = 1 - 5x

The domain is given as:

(-2,1,6)

Substitute these values in y = 1 - 5x

y = 1 - 5(-2) = 11

y = 1 - 5(1) = -4

y = 1 - 5(6) = -29

Hence, the corresponding range of the domain is (11, -4, -29)

Read more about domain and range at:

brainly.com/question/1632425

#SPJ1

6 0
2 years ago
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