Answer:
Step-by-step explanation:
Given that a professor sets a standard examination at the end of each semester for all sections of a course. The variance of the scores on this test is typically very close to 300.

(Two tailed test for variance )
Sample variance =480
We can use chi square test for testing of hypothesis
Test statistic = 
p value = 0.0100
Since p <0.05 our significance level, we reject H0.
The sample variance cannot be claimed as equal to 300.
Answer: D for the first one and B for the second
Step-by-step explanation:
Answer:
Step-by-step explanation:
3(3)^2 + 5(3) + 25
3*3 = 9, 5*3 = 15
3(9) + 15 + 25
27 + 15 + 25 = 67
Answer:
The perimeter of the garden, in meters, is 
Step-by-step explanation:
Diagonal of a square:
The diagonal of a square is found applying the Pythagorean Theorem.
The diagonal of the square is the hypothenuse, while we have two sides.
Diagonal of 12m:
This means that
, side s. So





Factoring 72:
Factoring 72 into prime factors, we have that:
72|2
36|2
18|2
9|3
3|3
1
So

So, in simplest radical form:

Perimeter of the garden:
The perimeter of a square with side of s units is given by:

In this question, since 

The perimeter of the garden, in meters, is 
The corresponding range of the domain is (11, -4, -29)
<h3>How to determine the range?</h3>
The function is given as:
5x + y = 1
Make y the subject
y = 1 - 5x
The domain is given as:
(-2,1,6)
Substitute these values in y = 1 - 5x
y = 1 - 5(-2) = 11
y = 1 - 5(1) = -4
y = 1 - 5(6) = -29
Hence, the corresponding range of the domain is (11, -4, -29)
Read more about domain and range at:
brainly.com/question/1632425
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