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2 years ago

12

The femur is the upper leg bone, and the tibia is one of the lower leg bones. the average length of the fumer is 50.5 cm,and the

average length of the tibia is 43.03 cm. estimate the total length of the leg if the bones were placed end to end

1 answer:

Vilka [71]2 years ago

7 0

50.5 cm + 43.03 cm = 93.53

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What’s the correct answer for this?

Anvisha [2.4K]

Answer:

P = 4/13

Step-by-step explanation:

In a deck of 52 cards, there are 3 aces(spade, heart, diamond), 1 club ace, and 12 remaining club cards

=> The probability of randomly drawing 1 card that is an ace card or a club card:

P = number of elements/total number of elements

P = (3 + 1 + 12)/52

P = 16/52

P = 4/13

=> Option A is correct

8 0

3 years ago

Dean is ready to buy a new car. He has $24,000 to spend. The sales tax where he lives is 6%. He put his research on car prices i

mixer [17]

The most expensive car Dean can buy is the <span>4-door hatchback.
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22500 x .06 = 13501350 + 22500 = 23850
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5 0

3 years ago

Read 2 more answers

Phones-R-Us charges $16.95 per month and $0.05 per text message. Awesome Wireless charges $22.95 per

Dima020 [189]

Answer:

$S \leq 200$

Step-by-step explanation:

Given

Phone R-Us= $16.95 + $0.05 per SMS

Awesome Wireless = $22.95 + $0.02 per SMS

Required

Determine the number of SMS such that Awesome Wireless is greater or equal to Phone R-Us

Represent the SMS with S

For Phone R-Us, we have:

$SMS = 16.95 + 0.05S$

For Awesome Wireless, we have:

$SMS = 22.95 + 0.02S$

For Awesome Wireless is greater or equal to Phone R-Us, we have:

$22.95 + 0.02S \geq 16.95 + 0.05S$

Collect Like Terms

$0.02S - 0.05S \geq 16.95 - 22.95$

$-0.03S \geq -6$

Solve for S

$\frac{-0.03S}{-0.03} \geq \frac{-6}{-0.03}$

$S \leq 200$

<em>Hence: for Awesome Wireless to cost more or equal to Phone R-Us, the number of SMS must not exceed 200</em>

4 0

3 years ago

Whats the output if i square -6 as the input

nirvana33 [79]

Answer:

u mean:

$\sqrt{ - 6 \: } it \: can \: not \: work \: if \: negative \: integer \: inside \: so \: thats \: why \: answer \: would \: be \: not \: possible.$

answer is not possible.

7 0

3 years ago

Write p(x) = 21 + 24x + 6x2 in vertex form.

Helen [10]

To do this, complete the square:

p(x) = 21 + 24x + 6x2 => <span>p(x) = 6x2 + 24x + 21

Rewrite the first 2 terms as

6(x^2 + 4x)

then you have </span><span>p(x) = 6(x2 + 4x ) + 21

Now complete the square of x^2 + 4x:

p(x) = 6(x^2 + 4x + 4 - 4) + 21
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p(x) = 6(x+2)^2 - 3 this is in vertex form now.

We can read off the coordinates of the vertex from this: (-2, -3)</span>

8 0

3 years ago