Answer:
8
Step-by-step explanation:
this 3 qub root of 512 is 8
I'm assuming the limit is supposed to be

Multiply the numerator by its conjugate, and do the same with the denominator:

so that in the limit, we have

Factorize the first term in the denominator as

The
terms cancel, leaving you with

and the limand is continuous at
, so we can substitute it to find the limit has a value of -1/18.
If the roots of the equation f(x)=0 are -4,-1, 2 and 5, then binomials (x+4), (x+1), (x-2) and (x-5) are factors of needed polynomial.
Thus, the polynomial will have form
where a is real coefficient (positive or negative). This polynomial has degree 4 as needed.
The form of the graph depends on the sign of coefficient a. Attached diagrams show two different cases of possible forms of graphs (first one for positive coefficient a, second one for negative coefficient a).