Can someone explain this to me? Please solve step by step. I don't know how to do this.

Mathematics

1 answer:

ololo11 [35]3 years ago

6 0

Given,

y = -3x+1 (EQ1)
y = 2x-4 (EQ2)

Equate EQ1 and EQ2

EQ1 = EQ2
-3x+1 = 2x-4
-3x-2x = -4-1
x = 1

y = -3x+1
y = -3(1)+1
y = -3+1
y = -2

(1, -2)
~B

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Hope this helps!

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Read 2 more answers

-4x-15y=-17<br>-x+5y=-13<br><img src="https://tex.z-dn.net/?f=%20-%204x%20-%2015y%20%3D%20%20-%2017%20%20%5C%5C%20%20-%20x%20%2B

salantis [7]

To solve this system of linear equations we need a little trick called elimination steps are below

we are given the following system of equations
$- 4x - 15y = - 17$
$- x + 5y = - 13$
if you look at the x variables in both equations you can see that we can easily eliminate them by multiplying the bottom equation by -4 as so
$- 4x - 15y = - 17$
$- 4( - x + 5y = - 13)$
simplify and we get
$- 4x - 15y = - 17$
$4x - 20y = 52$
now we can combine like terms on each side with the x's cancelling and get

$- 35y = 35$
now divide off -35
$y = - 1$
great now we can go back to our original system and pick a equation and substitute y back in to find x lets use

$- x + 5y = 13$
so now we substitute y and get
$- x + 5( - 1) = 13$
$- x - 5 = 13$
$- x = 17$
$x = - 17$

now we put x and y into one coordinate (x,y)
so now our FINAL ANSWER IS
(-17,-1)

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