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zhannawk [14.2K]
3 years ago
15

A small ranger vehicle has a soft, ragtop roof. When the car is at rest, the roof is flat. When the car is cruising at highway s

peeds with its windows rolled up, does the roof bow upwards, remain flat, or bow downwards
Physics
1 answer:
Nezavi [6.7K]3 years ago
5 0

Answer:

roof bow upwards

Explanation:

The top of the roof of the small ranger vehicle will bow upwards. This is as a result of gas pressure on the soft ragtop roof.

  • As air begins to fill the vehicle, pressure resonates in all direction proportionally.
  • The pressure of the air will be greater than that which the roof can withstand and this forces the roof sky up.
  • It is a common scene when we see roof of ragtop vehicles bowing upwards into the sky.
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Correct Answers is A.

The machines gives us some mechanical advantage. This means the mechanical average makes the work output greater than the work input
Simple most example is a lever. The force applied is smaller and the output work is larger as compared to input.

Option B cannot be true, as there must be a force to get some work done.
Option C and D are inverse of what a machine is designed for. A small force can be exerted through a large distance to have a large force exerted through a small distance. Common Example of this principle is a screw opener. 
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7 0
3 years ago
The measurement 0.025563 g should be reported as?
Tomtit [17]
The given mass is 0.025563 g.

Examine the given choices.
a. 0.026 g
This uses 2 significant digits, with rounding to the 3rd decimal place.

b. 2.5 x 10² g = 250 g.
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c. 0.025 g.
This uses 2 significant digits. It is inaccurate because it does not use rounding to the 3rd decimal place.

d. 0.02 g
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7 0
3 years ago
An aircraft travels a distance of 50km in a straight line
Juliette [100K]

Answer:

200 m/s

Explanation:

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6 0
2 years ago
A single-slit diffraction pattern is formed by monochromatic electromagnetic radiation from a distant source passing through a s
tatiyna

Answer:

a. λ = 647.2 nm

b. I₀  9.36 x 10⁻⁵

Explanation:

Given:

β = 56.0 rad , θ = 3.09 ° , γ = 0.170 mm = 0.170 x 10⁻³ m

a.

The wavelength of the radiation can be find using

β = 2 π / γ * sin θ

λ = [ 2π * γ * sin θ ] / β

λ = [ 2π * 0.107 x 10⁻³m * sin (3.09°) ] / 56.0 rad

λ = 647.14 x 10⁻⁹ m  ⇒  λ = 647.2 nm

b.

The intensity of the central maximum I₀

I = I₀ (4 / β² ) * sin ( β / 2)²

I = I₀ (4 / 56.0²) * [ sin (56.0 /2) ]²

I = I₀  9.36 x 10⁻⁵

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3 years ago
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