Question

The force an ideal spring exerts on an object is given by , where measures the displacement of the object from its equilibrium position. If , how much work is done by this force as the object moves from to

Answer 1

Answer:

The correct answer is "1.2 J".

Explanation:

Seems that the given question is incomplete. Find the attachment of the complete query.

According to the question,

• x₁ = -0.20 m
• x₂ = 0 m
• k = 60 N/m

Now,

⇒ $W=\int_{x_1}^{x_2}F \ dx$

⇒      $=\int_{x_1}^{x_2}-kx \ dx$

⇒      $=-k \int_{-0.20}^{0}x \ dx$

By putting the values, we get

⇒      $=-(60)[\frac{x^2}{2} ]^0_{-0.20}$

⇒      $=-60[\frac{0}{2}-\frac{0.04}{2} ]$

⇒      $=1.2 \ J$