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Usimov [2.4K]
3 years ago
6

What is the physical representation of the area under a force versus extension or compression curve?

Physics
1 answer:
lidiya [134]3 years ago
5 0

The compression curve would be theoretically given for a system of bodies in which the spring applies the force (Although in the same way the following process can be extrapolated to any system, depending on the type of Force to consider) For a spring mass system, the strength is given by Hooke's law as

F = Kx

Where,

K  = Spring constant

x = Displacement

If we integrate based on distance we would have

\int F = \int K x dx

This integral represents the area under the Force Curve based on each distance segment traveled.

\int F = K \int xdx

\int F = K (\frac{1}{2} x^2)

\int F = \frac{1}{2} Kx^2

This is the same formula that represents the elastic potential energy of a body. Therefore the correct answer is D.

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6 0
3 years ago
For which length of wire are the readings of resistance the most precise
levacccp [35]
The resistance of a wire is directly proportional to the length of the wire. That is the longer the length of the wire, the higher the resistance and the shorter the length of the wire, the smaller the resistance.
7 0
3 years ago
Under ideal conditions (no atmospheric interference of any kind), if I hit a golf ball at an angle of 25 degrees at an initial s
g100num [7]

Answer:

The required angle is (90-25)° = 65°

Explanation:

The given motion is an example of projectile motion.

Let 'v' be the initial velocity and '∅' be the angle of projection.

Let 't' be the time taken for complete motion.

Let 'g' be the acceleration due to gravity

Taking components of velocity in horizontal(x) and vertical(y) direction.

v_{x} =  v cos(∅)

v_{y} =  v sin(∅)

We know that for a projectile motion,

t =\frac{2vsin(∅)}{g}

Since there is no force acting on the golf ball in horizonal direction.

Total distance(d) covered in horizontal direction is -

d = v_{x}×t = vcos(∅)×\frac{2vsin(∅)}{g} = \frac{v^{2}sin(2∅) }{g}.

If the golf ball has to travel the same distance 'd' for same initital velocity v = 23m/s , then the above equation should have 2 solutions of initial angle 'α' and 'β' such that -

α +β = 90° as-

d = \frac{v^{2}sin(2α) }{g} = \frac{v^{2}sin(2[90-β]) }{g} =\frac{v^{2}sin(180-2β) }{g} = \frac{v^{2}sin(2β) }{g} .

∴ For the initial angles 'α' or 'β' , total horizontal distance 'd' travelled remains the same.

∴ If α = 25° , then

     β = 90-25 = 65°

∴ The required angle is 65°.

5 0
3 years ago
Read 2 more answers
The nucleus of the polonium isotope 214 Po (mass 214 u) is radioactive and decays by emitting an alpha particle (a helium nucleu
amid [387]

Answer:

368224.29906 m/s

Explanation:

M = Mass of Polonium nucleus = 214 u

V = Velocity of nucleus

m = Mass of Helium nucleus = 4 u

v = Velocity of alpha particle = 1.97\times 10^7\ m/s

In this system the momentum is conserved

MV+mv=0\\\Rightarrow MV=-mv\\\Rightarrow 214V=-4\times 1.97\times 10^7\\\Rightarrow V=\dfrac{-4\times 1.97\times 10^7}{214}\\\Rightarrow V=368224.29906\ m/s

The recoil speed of the nucleus that remains after the decay is 368224.29906 m/s

6 0
3 years ago
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The shoemaker-near spacecraft explored two asteroids, mathilde and eros. a big difference between them is that:________.
Oksi-84 [34.3K]

A big difference between Mathilde and Eros is that Mathilde represents a group of separate rocks whereas Eros is a solid rock.

<h3>What is an asteroid?</h3>

An asteroid is a celestial body composed of different types of rocky materials (generally clay but also silicate) and also metals (especially Fe).

An asteroid may have different sizes and some of them can be huge as dwarf planets that travel across the universe.

In conclusion, a big difference between Mathilde and Eros is that Mathilde represents a group of rocks whereas Eros is a solid rock.

Learn more about asteroids here:

brainly.com/question/11996385

#SPJ1

4 0
2 years ago
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