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3 years ago

Hydrogen gas was cooled from 150c to 50c. its new volume is 75.0 ml. what was its original volume

1 answer:

6 0

From the information given, the hydrogen gas was cooled from a temperature of 150 °C to 50 °C. The final volume of the gas after being cooled came to 75ml. To find out its original volume, we need to apply Charles law which is expressed as : V1 /T1 = V2 /T2 Where V1 is original volume Where T1 is original temperature Where V2 is the final volume Where T2 is the final temperature. We need V1 so V1 = (V2 × T1) ÷ T2 V1 = (75 × 150) ÷ 50 V1 = 225 ml Original volume of the gas was 225 ml

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A golfer is on the edge of a 12.5 m bluff overlooking the 18th hole which is located 60 m from the base of the bluff. She launch

Lina20 [59]

Answer:

The ball impact velocity i.e(velocity right before landing) is 6.359 m/s

Explanation:

This problem is related to parabolic motion and can be solved by the following equations:

$x=V_{o}cos \theta t$ ----------------------(1)

$y=y_{o}+V_{o} sin \theta t - \frac{1}{2}gt^{2}$ ---------(2)

$V=V_{o}-gt$ ----------------------- (3)

Where:

x = m is the horizontal distance travelled by the golf ball

$V_{o}$ is the golf ball's initial velocity

$\theta=0\°$ is the angle (it was a horizontal shot)

t is the time

y is the final height of the ball

$y_{o}$ is the initial height of the ball

g is the acceleration due gravity

V is the final velocity of the ball

Step 1: finding t

Let use the equation(2)

$t=\sqrt{\frac{2 y_{o}}{g}}$

$t=\sqrt{\frac{2 (12.5 m)}{9.8 m/s^{2}}}$

$t=1.597$ s

Substituting (6) in (1):

$67.1 =V_{o} cos(0\°) 1.597$ -------------------(4)

Step 2: Finding $V_{o}$ :

From equation(4)

$67.1 =V_{o}(1) 1.597$

$V_0 = \frac{6.71}{1.597}$

$V_{o}=42.01$ m/s (8)

Substituting $V_{o}$ in (3):

$V=42.01 -(9.8)(1.597)$

v =42 .01 - 15.3566

V=26.359 m/s

5 0

2 years ago

A 21 N block rests on a horizontal surface. The coefficients of static and kinetic friction between the surface and the block ar

Georgia [21]

Answer:

a)15 N

b)12.6 N

Explanation:

Given that

Weight of block (wt)= 21 N

μs = 0.80 and μk = 0.60

We know that

Maximum value of static friction given as

Frs = μs m g = μs .wt

by putting the values

Frs= 0.8 x 21 = 16.8 N

Value of kinetic friction

Frk= μk m g = μk .wt

By putting the values

Frk= 0.6 x 21 = 12.6 N

When T = 15 N

Static friction Frs= 16.8 N

Here the value of static friction is more than tension T .It means that block will not move and the value of friction force will be equal to the tension force.

Friction force = 15 N

When T= 35 N

Here value of tension force is more than maximum value of static friction that is why block will move .We know that when body is in motion then kinetic friction will act on the body.so the value of friction force in this case will be 12.6 N

Friction force = 12.6 N

8 0

3 years ago

Please help!

julsineya [31]

Answer:

Answer:

3 g/cm

Explanation:

Mass of stone = 30 g

Initial volume of cylinder = 50 cm

Increased volume = 60 cm

Volume = 60-50

= 10 cm

Density of stone = Mass/Volume

= 30/10

= 3 g/ml as 1 ml = 1 cm

= 3 g/ml

Explanation:

6 0

2 years ago

which of the following types of exercise increase lean body mass?. A.) cardiorespiratory fitness. B.) flexibility. C.) muscular

Sunny_sXe [5.5K]

A lean body mass that the cholesterol level in the body is low and that the excess fats in the body are getting rid off as much as one can. In this case, the exercises A.) cardiorespiratory fitness such as jogging and <span>C.) muscular strength and endurance such as body building, abs routines are employed. Answer is D. both A and C.</span>

7 0

3 years ago

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During energy conversions, some energy is always lost as _____. light , heat , electricity or chemical energy?

masya89 [10]

Heat because in a machine heat must come out to follow the law of conservation of energy

3 0

2 years ago

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