Hydrogen gas was cooled from 150c to 50c. its new volume is 75.0 ml. what was its original volume

1 answer:

6 0

From the information given, the hydrogen gas was cooled from a temperature of 150 °C to 50 °C. The final volume of the gas after being cooled came to 75ml. To find out its original volume, we need to apply Charles law which is expressed as : V1 /T1 = V2 /T2 Where V1 is original volume Where T1 is original temperature Where V2 is the final volume Where T2 is the final temperature. We need V1 so V1 = (V2 × T1) ÷ T2 V1 = (75 × 150) ÷ 50 V1 = 225 ml Original volume of the gas was 225 ml

You might be interested in

How does increasing the distance between charged objects affect the electric force between them?

mina [271]

Answer: energy force

Explanation:

6 0

3 years ago

Would the frequency of the angular simple harmonic motion (SHM) of the balance wheel increase or decrease if the dimensions of t

storchak [24]

Answer:

Yes the frequency of the angular simple harmonic motion (SHM) of the balance wheel increases three times if the dimensions of the balance wheel reduced to one-third of original dimensions.

Explanation:

Considering the complete question attached in figure below.

Time period for balance wheel is:

$T=2\pi\sqrt{\frac{I}{K}}$

$I=mR^{2}$

m = mass of balance wheel

R = radius of balance wheel.

Angular frequency is related to Time period as:

$\omega=\frac{2\pi}{T}\\\omega=\sqrt{\frac{K}{I}} \\\omega=\sqrt{\frac{K}{mR^{2}}$

As dimensions of new balance wheel are one-third of their original values

$R_{new}=\frac{R}{3}$

$\omega_{new}=\sqrt{\frac{K}{mR_{new}^{2}}}\\\\\omega_{new}=\sqrt{\frac{K}{m(\frac{R}{3})^{2}}}\\\\\omega_{new}={3}\sqrt{\frac{K}{mR^{2}}}\\\\\omega_{new}={3}\omega$