-9-16m=7
-16m=7+9
-16m=16
-m=1
m=-1
From the statement you can find the function that represents the percent of strontium-90 that remains after t years of the nuclear accident.
Call P the percent:
---> P = e ^ (- 0.025t)
Now you can also estimate the half-life of the isotope strontium-90:
Call Pi the initial percent and P2 the half percent:
P2 = 0.5 * P initial =>
P2 = 0.5 * Pinitial = Pinitial * e ^ (-0.025 t)
=> 0.5 = e ^ (-0.025t)
=> ln 0.5 = -0.025t
=> t = - ln (0.5) / 0.025
=> t = 27.7 years <----- half-time
9514 1404 393
Answer:
-7x^2 +8x -10
Step-by-step explanation:
Combine like terms in the usual way.
(-3x^2 +5x -8) -(4x^2 -3x +2)
= -3^2 +5x -8 -4x^2 +3x -2
= (-3-4)x^2 +(5+3)x +(-8-2)
= -7x^2 +8x -10
Answer:Answer:
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Explanation:
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Step-by-step explanation:
Answer:
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Explanation:
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