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Luba_88 [7]
4 years ago
9

Complete the coordinate proof of the theorem. Given: A B C D is a parallelogram. Prove: The diagonals of A B C D bisect each oth

er. Art: A parallelogram is graphed on a coordinate plane. The horizontal x-axis and vertical y-axis are solid. The vertex labeled as A lies on begin ordered pair 0 comma 0 end ordered pair. The vertex labeled as B lies on begin ordered pair a comma 0 end ordered pair. The vertex labeled as D lies on begin ordered pair c comma b end ordered pair. The vertex C is unlabeled. Diagonals A C and B D are drawn by a dotted lines. Enter your answers in the boxes. The coordinates of parallelogram ABCD are A(0, 0) , B(a, 0) , C( , ), and D(c, b) . The coordinates of the midpoint of AC¯¯¯¯¯ are ( , b2 ). The coordinates of the midpoint of BD¯¯¯¯¯ are ( a+c2 , ). The midpoints of the diagonals have the same coordinates. Therefore, AC¯¯¯¯¯ and BD¯¯¯¯¯ bisect each other.

Mathematics
2 answers:
Kamila [148]4 years ago
5 0

Answer:


Step-by-step explanation:

THESE ARE THE CORRECT ANSWERS

Paraphin [41]4 years ago
3 0

Answer: 1=a+c

2=b

3=a+c/2

4=b/2

Step-by-step explanation: Took the test

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<h3>How to find the tangent of an angle?</h3>
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Researching the problem in the internet, it is found that for the <em>right triangle</em> in this problem:

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Applying the Pythagorean Theorem, we have that:

6^2 + x^2 = 11^2

36 + x^2 = 121

x^2 = 85

x = \sqrt{85}

Considering that the tangent is the length of the opposite leg divided by the length of the adjacent leg, we have that:

\tan{F} = \frac{6}{\sqrt{85}} \times \frac{\sqrt{85}}{\sqrt{85}} = \frac{6\sqrt{85}}{85}

To learn more about tangent, you can take a look at brainly.com/question/24680641

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I attached my work, hopefully it is clear. Same day tickets cost $40 and Advance tickets cost $25.

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