Whats bigger three fifths or 0.35

What is the measure of angle x?

blondinia [14]

Answer:

46

Step-by-step explanation:

Because they are alternate, duh

6 0

2 years ago

Read 2 more answers

(20+80 divided by 2x8) divided [(54 divided by 9+14)divided by 4]

lesya692 [45]

Answer:

80

Step-by-step explanation:

Let's write out the equation:

8(20+80/2)/[(54/9+14)/4]

For the first part we get 8(100/2)

Then 50x8

Then 400

For the second part we have (6+14)/4 as we divide 54 by 9. PEMDAS

Then 20/4

Then 5

So our final answer is 400/5 which is 80.

Hope this helps!

7 0

3 years ago

A radio is on sale for half price. Let y be its original price. Write an expression that tells its sale price.

svetlana [45]

Answer:

50% off of y

Step-by-step explanation:

4 0

3 years ago

7. Calculate the selling price of a $350 camera with a 35% mark-up sale price.

lubasha [3.4K]

Answer:

10) 3/5=a/15

a=9

9) 6/100×300

18$

8) 100-57.5

=42.5percent

7) 35/100×350

.=$122.5

3 0

3 years ago

Determine the number of possible solutions for a triangle with B=37 degrees, a=32, b=27

vladimir1956 [14]

Answer:

Two possible solutions

Step-by-step explanation:

we know that

Applying the law of sines

$\frac{a}{sin(A)}=\frac{b}{Sin(B)}=\frac{c}{Sin(C)}$

we have

$a=32\ units$

$b=27\ units$

$B=37\°$

step 1

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{Sin(B)}$

substitute the values

$\frac{32}{sin(A)}=\frac{27}{Sin(37\°)}$

$sin(A)=(32)Sin(37\°)/27=0.71326$

$A=arcsin(0.71326)=45.5\°$

The measure of angle A could have two measures

the first measure-------> $A=45.5\°$

the second measure -----> $A=180\°-45.5\°=134.5\°$

step 2

Find the first measure of angle C

Remember that the sum of the internal angles of a triangle must be equal to $180\°$

$A+B+C=180\°$

substitute the values

$A=45.5\°$

$B=37\°$

$45.5\°+37\°+C=180\°$

$C=180\°-(45.5\°+37\°)=97.5\°$

step 3

Find the first length of side c

$\frac{a}{sin(A)}=\frac{c}{Sin(C)}$

substitute the values

$\frac{32}{sin(37\°)}=\frac{c}{Sin(97.5\°)}$

$c=Sin(97.5\°)\frac{32}{sin(37\°)}=52.7\ units$

therefore

the measures for the first solution of the triangle are

$A=45.5\°$ , $a=32\ units$

$B=37\°$ , $b=27\ units$

$C=97.5\°$ , $b=52.7\ units$

step 4

Find the second measure of angle C with the second measure of angle A

Remember that the sum of the internal angles of a triangle must be equal to $180\°$

$A+B+C=180\°$

substitute the values

$A=134.5\°$

$B=37\°$

$134.5\°+37\°+C=180\°$

$C=180\°-(134.5\°+37\°)=8.5\°$

step 5

Find the second length of side c

$\frac{a}{sin(A)}=\frac{c}{Sin(C)}$

substitute the values

$\frac{32}{sin(37\°)}=\frac{c}{Sin(8.5\°)}$

$c=Sin(8.5\°)\frac{32}{sin(37\°)}=7.9\ units$

therefore

the measures for the second solution of the triangle are

$A=45.5\°$ , $a=32\ units$

$B=37\°$ , $b=27\ units$

$C=8.5\°$ , $b=7.9\ units$

6 0

3 years ago