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Zanzabum
3 years ago
7

Whats bigger three fifths or 0.35

Mathematics
1 answer:
never [62]3 years ago
7 0
3/5. Because 35/100 is simplified to only3/10
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Mean, medium, & mode of 17, 6, 20, 11, 13, 20, 18
kodGreya [7K]

Step-by-step explanation:

medium -11

I don't know about mean & mode

5 0
3 years ago
Which sentence best contrasts Greg’s father and Lemon Brown, in "The Treasure of Lemon Brown”? Lemon Brown has shown a deep conc
Vika [28.1K]

Answer:

the correct answer will be B i took the test and got a 100%

Step-by-step explanation:

B. Lemon Brown has lived a more exciting life of a musician, while Greg’s father lives a more stable existence as a postal worker.

6 0
3 years ago
— 2y – Зу +8 = 8 — 5у – 12
jasenka [17]

Answer:

No Solution.

Step-by-step explanation:

Equality equation:

— 2y – Зу +8 = 8 — 5у – 12  (Given)

-5y + 8 = -4 - 5y (distributive property of equality)

-5y = -12 - 5y (subtraction property of equality)

= -12 (addition property of equality)

when you add 5y on both sides it cancels the 5y out, it's no solution.

<em><u>Ace-The Kid Laroi</u></em>

6 0
3 years ago
Please Help !!!
solong [7]
Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)

moles LiCl required = 4.37
mass LiCl = 4.37 mol x 42.394 g/mol=185.3 g


Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
moles Cu reacted = 6.3 / 2 = 3.15
moles Cu in excess = 4.2 - 3.15 =1.05

N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
moles H2 in excess = 5.00 - 4.56 =0.44
mass H2 in excess = 0.44 mol x 2.016 g/mol=0.887 g
5 0
4 years ago
4.) Which best describes the relationship between &lt; AFB and &lt; AFD?
MAVERICK [17]

Answer:

C. Supplementary angles

Step-by-step explanation:

Given

<AFB = 72

Required

Relationship of <AFB and <AFD

<AFB and <AFD are on a straight line and angle on a straight line is 180

From the presentation of both angles,

<AFB + <AFD = 180

Substitute 72 for <AFB

72 + <AFD = 180

Make <AFB the subject of formula

<AFD = 180 - 72

<AFD = 108

Since both <AFB and <AFD sums to 180, then they are supplementary angles.

Hence, the relationship between both angles is supplementary angles

5 0
4 years ago
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