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Alinara [238K]
3 years ago
12

What is the value of the expression? (5/2)2+3/4^3

Mathematics
2 answers:
wel3 years ago
7 0
<span><span>12</span> + <span>15</span> + <span>45</span> + 1 <span>23</span> = <span>196</span> = 3<span>16</span> ≅ 3.166667</span>
irakobra [83]3 years ago
5 0
Assuming you put this correctly and it's 3/4^3 not 3/(4^3); The answer would be 2.5*2+3/4^3 = 5 + 3/4^3 = 5.42. However, if it's the latter your answer would instead be 5.05.
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Use completing the square to solve the equation x2 - 10x = -8.
Kay [80]

Answer:

x^2 - 10x + 25 = 17

Step-by-step explanation:

Please use " ^ " to denote exponentation:

x^2 - 10x = -8

x^2 - 10x + 25 = 17

x^2 - 10x + 25 = -8

x^2 - 10x - 25 = -33

Begin with x^2 - 10x = -8.  Here's the process for completing the square:

1.  Take half of the coefficient of x and square the result:

    (1/2)(-10) = -5, and then (-5)^2 = + 25

2.  Add this 25 to the first two terms of x^2 - 10x = -8 and also to the      constant -8:    x^2 - 10x + 25 = -8 + 25, or     x^2 - 10x + 25 = 17

3.  Match this result to one of the given possible answers.  Turns out that the given possible answer matching our result is the first one:

x^2 - 10x + 25 = 17

     

7 0
3 years ago
1)-11 + __ = 15<br> I really need help
katrin [286]

Answer:

26

Step-by-step explanation: You basically add 11 them you are at 0 then add 15 to that number and you get 11+15=26 thats ur answer

6 0
3 years ago
Read 2 more answers
Triangle ABC has vertices A(-2, 3), B(0, 3), and C(-1,-1). Find the coordinates of the image after a reflection over the
motikmotik

<u>Given</u>:

Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).

We need to determine the coordinates of the image after a reflection over the x - axis.

Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.

<u>Coordinates of the point A':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point A(-2,3), we get;

(-2,3)\rightarrow (-2,-3)

Thus, the coordinates of the point A' is (-2,-3)

<u>Coordinates of the point B':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point B(0,3), we get;

(0,3)\rightarrow (0,-3)

Thus, the coordinates of the point B' is (0,-3)

<u>Coordinates of the point C':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point C(-1,-1), we get;

(-1,-1)\rightarrow (-1,1)

Thus, the coordinates of the point C' is (-1,1)

Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)

8 0
3 years ago
Work out the value of 4 lots of 10​
nasty-shy [4]

Answer:

40

Step-by-step explanation:

4 lots of 10 is 10+10+10+10 or 4 x 10

3 0
3 years ago
Read 2 more answers
Mathhhhhhhhhhhhhhhhhh
xxTIMURxx [149]

Answer:

formal proof

Step-by-step explanation:

https://quizlet.com/230868297/geometry-u2-review-flash-cards/

7 0
3 years ago
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